Answer:
Explanation:
kinematic equation (g will have a negative value if we assume UP is positive)
v² = u² + 2as
a) v = √(0² + 2(g)(y - h))
b) v = √(vi² + 2(g)(y - h))
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-- The circumference of the track is (2 · π · radius).
Circumference = (2 · π · 1.67m) = 10.49 meters .
-- The train's speed is (31.5 cm) / (10.49 m) of the track's circumference, per second. That's ...
(31.5 cm) · (1m / 100cm) / (10.49 m / circumference) =
(31.5 / 100 · 1,049) (cm · m / cm · m) =
= 0.030 of the circumference per second.
The train performs 0.03 revolution per second.
It takes (1/0.03) = about 33.3 seconds to complete one revolution of the track.
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Answer:
The Work Done is
Explanation:
Since , the equipment is pulled in horizontal horizontal plane.
Therefore, its normal reaction must be equal to its weight.
So, Normal reaction,
We know, frictional force ,
(Where N is Normal reaction and is coefficient of kinetic friction )
Therefore,
We know ,
( Here D is distance covered by the force)
Putting, D=1000 m.
We get , Work Done