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musickatia [10]
4 years ago
13

The function of a cell depends primarily on its ?

Physics
1 answer:
Schach [20]4 years ago
8 0
<span>Organelles which are very important in giving nutrients. During cellular respiration, the food molecules such as glucose, are oxidized to carbon dioxide (CO2) and water (H2O) and trapped in ATP (Adenosine triphosphate) form for further us of cell’s activities. ATP’s are formed at mitochondria – the cell’s powerhouse. This type of organelle takes and breaks nutrients absorbed by the cell and creates energy afterward. The energy from ATP is then used by the body in kinetic activities like running & walking or involuntary activities like breathing, blood circulation, stimulus-responding, etc.</span>
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Lifting a rope A mountain climber is about to haul up a 50-m length of hanging rope. How much work will it take if the rope weig
timama [110]

Answer:

780 J

Explanation:

W=\int _{\:0}^{50}0.624xdx

4 0
2 years ago
A shell is fired from the ground with an initial speed of 1.74 ✕ 103 m/s at an initial angle of 58° to the horizontal.
ValentinkaMS [17]

Answer:

a) horizontal range s=277671.77 m

b) time the shell is in motion 301.143 s

Explanation:

Is a parabolic movement so the velocity have two components:

v = 1.74 x 10^{3}  ( \frac{m}{s} )

\alpha = 58°

v_{y} =v*Sen (\alpha )\\v_{x} =v*Cos (\alpha )

v_{y} =1740*Sen (58 )\\v_{x} =1740*Cos (58)

v_{y} = 1475.603 \frac{m}{s}\\v_{x} = 922.059 \frac{m}{s}\\

t= \frac{2*v_{y} }{g}

t= \frac{2*1475.603 }{9.8}

t= 301.143 s

v= \frac{s}{t} \\s= v_{x}*t

s= 922.059 \frac{m}{s} * 301.143 s

s = 277671.77 m

4 0
4 years ago
What is a system of knowledge and the methods used to find that knowledge
IceJOKER [234]
The answer to your question is "science"
5 0
4 years ago
Read 2 more answers
A body-centered cubic lattice has a lattice constant of 4.83 Ă. A plane cutting the lattice has intercepts of 9.66 Å, 19.32 Å, a
anastassius [24]

Answer:

Miller Indices are [2, 4, 3]

Solution:

As per the question:

Lattice Constant, C = 4.83 \AA

Intercepts along the three axes:

\bar{x} = 9.66 \AA

\bar{x} = 19.32 \AA

\bar{x} = 14.49 \AA

Now,

Miller Indices gives the vector representation of the atomic plane orientation in the lattice and are found by taking the reciprocal of the intercepts.

Now, for the Miller Indices along the three axes:

a = \frac{1}{9.66}

b = \frac{1}{19.32}

c = \frac{1}{14.49}

To find the Miller indices, we divide a, b and c by reciprocal of lattice constant 'C' respectively:

a' = \frac{\frac{1}{9.66}}{\frac{1}{4.83}} = \frac{1}{2}

b' = \frac{\frac{1}{19.32}}{\frac{1}{4.83}} = \frac{1}{4}

c' = \frac{\frac{1}{14.49}}{\frac{1}{4.83}} = \frac{1}{3}

7 0
3 years ago
A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the
alex41 [277]

Answer:

(a)v_1 = a_1t_1 = 1.76 t_1

(b) It won't hit

(c) 110 m

Explanation:

(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1

v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1

(b) The velocity of the car before the driver begins braking is

v_1 = 1.76*20 = 35.2m/s

The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2

We can use the following equation of motion to calculate how far the car has travel since braking to stop

s_2 = v_1t_2 + a_2t_2^2/2

s_2 = 35.2*5 - 7.04*5^2/2 = 88 m

Also the distance from start to where the driver starts braking is

s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

(c) The distance from the limb to where the car stops is 550 - 440 = 110 m

8 0
3 years ago
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