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matrenka [14]
4 years ago
10

A container filled with a sample of an ideal gas at the pressure of 150 Kpa. The gas is compressed isothermally to one-third of

its original volume. What is the new pressure of the gas a)-900 kpa b)- 300 kpa c)- 450 kpa d)- 600 kpa
Engineering
1 answer:
lyudmila [28]4 years ago
7 0

Answer: c) 450 kPa

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

P_1V_1=P_2V_2  

where,

P_1 = initial pressure of gas  = 150 kPa

P_2 = final pressure of gas  = ?

V_1 = initial volume of gas   = v L

V_2 = final volume of gas  = \frac{v}{3}L

150\times v=P_2\times \frac{v}{3}  

P_2=450kPa

Therefore, the new pressure of the gas will be 450 kPa.

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A vineyard owner is planting several new rows of grapevines, and needs to know how many grapevines to plant in each row. She has
boyakko [2]

Answer:

Finally, display the number of grapevines that will fit in the row

Explanation:

A vineyard owner is planting several new rows of grapevines, and needs to know how many grapevines to plant in each row. She has determined that after measuring the length of a future row, she can use the following formula to calculate the number of vines that will fit in the row, along with the trellis end-post assemblies that will need to be constructed at each end of the row:

V=R-2E/S

The terms in the formula are:

V is the number of grapevines that will fit in the row.

R is the length of the row, in feet.

E is the amount of space, in feet, used by an end-post assembly.

S is the space between vines, in feet.

Write a program that makes the calculation for the vineyard owner. The program should ask the user to input the following:

• The length of the row, in feet

• The amount of space used by an end-post assembly, in feet

• The amount of space between the vines, in feet

Once the input data has been entered, the program should calculate and display the number of grapevines that will fit in the row.

• Declare the variables amountSpace, vinesSpace, and grapevines of double type.

• Prompt and read the length of the row, in feet, the amount of space, in feet, and the space between vines, in feet.

• Calculate the number of grapevines that will fit in the row using the below formula:

grapvines=(rowLength-2*amountSpace)/vinesSpace;

• Finally, display the number of grapevines that will fit in the row.

8 0
3 years ago
What should i do to my nissan 350z, twin charge it or have twin turbos, to twin turbos with a super charger? i want it to be ove
bulgar [2K]

Answer:

A

Explanation:

It just makes sense

4 0
3 years ago
At what distance from a point charge of 8.0 μC would the electrical potential be 4.8 × 104 V? (ke = 8.99 × 109 N⋅m2/C2)
kotegsom [21]

Answer:

1.498 m

Explanation:

Electric potential due to a point charge V = K × Q / r

4.8 × 10 ⁴ V = 8.99 × 10⁹ N.m²/C² × 8 × 10⁻⁶ C / r

r = 8.99 × 10⁹ N.m²/C² × 8 × 10⁻⁶ C / 4.8 × 10 ⁴ V = 1.498 m

5 0
3 years ago
Oxygen enters an insulated 14.2-cm-diameter pipe with a velocity of 60 m/s. At the pipe entrance, the oxygen is at 240 kPa and 2
MatroZZZ [7]

Answer:

Entropy generation==0.12 KW/K

Explanation:

s_2-s_1=C_p\ln \frac{T_2}{T_1}-R\ln \frac{P_2}{P_1}

s_2-s_1=0.891\ln \frac{291}{293}-0.2598\ln \frac{200}{240}

s_2-s_1=0.0412\frac{KJ}{kg-K}

Mass flow rate= \rho\times\dfrac{\pi}{4}d^2V

\rho_1=\dfrac {P_1}{RT_1}

\rho_1=\dfrac {240}{0.2598\times 293}

\rho_1=3.51\frac{kg}{m^3}

mass flow rate=\rho_1A_1V_1

So by putting the values

Mass flow rate=2.97 kg/s

So entropy generation=(2.97)(0.0412)

                                    =0.12 KW/K

8 0
4 years ago
Beryllium (Be) has an HCP unit cell for which the ratio of the lattice parameters c/a is 1.568. If the radius of the Be atom is
sweet-ann [11.9K]

Answer:

Unit cell volume will be

4.866*10^{-2}nm^{3}

8 0
3 years ago
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