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Alona [7]
3 years ago
5

What is the acceleration of a softball if it has a mass of 0.5 kg and hits the cathers glove with a force of 25n

Physics
1 answer:
ioda3 years ago
3 0
Acceleration is found if we have the force and mass. 

With the following equation: F = ma, we can find the missing values. 

F = 25n
M = 0.5 kg
a = ?

a = f/m
a = 25/0.5
a = 50

a = 50 m/s

So, the acceleration is 50 m/s^2 
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A rod 14.0 cm long is uniformly charged and has a total charge of 222.0 mc. determine (a) the magnitude and (b) the direction of
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Electric field due to a charged rod along its axis is given by

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here we know that

L = 14 cm

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r = 36 - 7 = 29 cm

Q = 222 mC

now we will have

E = \frac{(9 \times 10^9)(222 \times 10^{-3})}{(0.29)(0.43)}

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3 years ago
Place the following list in order of occurrence from oldest to most recent:
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Answer:

Explanation:

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At an outdoor market, a bunch of bananas attached to the bottom of a vertical spring of force constant 16.0 N/m is set into osci
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Answer:

Explanation:

Answer:

4.53 kg

Explanation:

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The formula for maximum speed is given by

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0.376 = ω x 0.2

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m = \frac{K}{\omega ^{2}}

m = \frac{16}{1.88 ^{2}}

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8 0
3 years ago
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A future use of space stations may be to provide hospitals for severely burned persons. It is very painful for a badly burned pe
inessss [21]

Answer:

1.5min

Explanation:

To solve the problem it is necessary to take into account the concepts related to Period and Centripetal Acceleration.

By definition centripetal acceleration is given by

a_c = \frac{V^2}{r}

Where,

V = Tangencial velocity

r = radius

With our values we know that

a_c = \frac{V^2}{r}

\frac{V^2}{r} = \frac{1}{10}g

Therefore solving to find V, we have:

V = \sqrt{\frac{1}{10}g*r}

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t = \frac{Perimeter}{Speed}

t = \frac{2\pi R}{V}

t = \frac{2\pi * 200}{14}

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6 0
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