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3 years ago

12

The distance between two subway station is 3 miles if a train travels between the two stations at an average speed of 60 mph how

many minutes does it take for the train to finish the trip between the two stations

1 answer:

Andreyy893 years ago

6 0

Answer:

It takes 3 minutes.

Explanation:

The distance between the two subways is 3 miles.

The train travels at an average speed of 60mph (miles per hour).

$\frac{60miles}{1 hour} * \frac{1hour}{60minutes} = \frac{1mile}{1minute}$

We have to convert hours to minutes and we do that by cancelling out the hours and replacing it with minutes.

There are 60 minutes in an hour so we use that, 1 hour/60 minutes and multiply it to the existing speed we have.

The result is 1 mile per minute.

We then multiply the miles by 3 since that is how much we want and we get 3 minutes.

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A package is dropped from an air balloon two times. In the first trial the distance between the balloon and the surface is Hand

enyata [817]

Answer:

<em>The final speed of the second package is twice as much as the final speed of the first package.</em>

Explanation:

<u>Free Fall Motion</u>

If an object is dropped in the air, it starts a vertical movement with an acceleration equal to g=9.8 m/s^2. The speed of the object after a time t is:

$v=gt$

And the distance traveled downwards is:

$\displaystyle y=\frac{gt^2}{2}$

If we know the height at which the object was dropped, we can calculate the time it takes to reach the ground by solving the last equation for t:

$\displaystyle t=\sqrt{\frac{2y}{g}}$

Replacing into the first equation:

$\displaystyle v=g\sqrt{\frac{2y}{g}}$

Rationalizing:

$\displaystyle v=\sqrt{2gy}$

Let's call v1 the final speed of the package dropped from a height H. Thus:

$\displaystyle v_1=\sqrt{2gH}$

Let v2 be the final speed of the package dropped from a height 4H. Thus:

$\displaystyle v_2=\sqrt{2g(4H)}$

Taking out the square root of 4:

$\displaystyle v_2=2\sqrt{2gH}$

Dividing v2/v1 we can compare the final speeds:

$\displaystyle v_2/v_1=\frac{2\sqrt{2gH}}{\sqrt{2gH}}$

Simplifying:

$\displaystyle v_2/v_1=2$

The final speed of the second package is twice as much as the final speed of the first package.

5 0

2 years ago

Two identical loudspeakers are driven in phase by a common oscillator at 750 Hz and face each other at a distance of 1.24 m. Loc

Juli2301 [7.4K]

Answer:

0.2286 m, 0.686 m and 1,143 m

therefore we see that there is respect even where the intensity is minimal

Explanation:

Destructive interference to the two speakers is described by the expression

Δr = (2n +1) λ/2

where r is the distance, λ the wavelength and n an integer indicating the order of the interference

let's locate the origin on the left speaker

let's find the wavelength with the equation

v = λ f

λ = v / f

we substitute

Δr = (2n + 1) v / 2f

let's calculate for difference values of n

Δr = (2n +1) 343/(2 750)

Δr = (2n + 1) 0.2286

we locate the different values for a minimum of interim

n Δr (m)

0 0.2286

1 0.686

2 1,143

therefore we see that there is respect even where the intensity is minimal

6 0

2 years ago

What area of science compares and describes quantities and movements of matter and energy?

qaws [65]

Answer:

the answer is physics

4 0

3 years ago

Two airplanes leave an airport at the same time.The velocity of the first airplane is 700 m/h at a heading of 31.3 the velocity

MArishka [77]

Here in order to find out the distance between two planes after 3 hours can be calculated by the concept of relative velocity

$v_{12} = v_1 - v_2$

here

speed of first plane is 700 mi/h at 31.3 degree

$v_1 = 700 cos31.3\hat i + 700 sin31.3\hat j$

$v_1 = 598.12\hat i + 363.7\hat j$

speed of second plane is 570 mi/h at 134 degree

$v_2 = 570 cos134 \hat i + 570 sin134 \hat j$

$v_2 = -396\hat i + 410\hat j$

now the relative velocity is given as

$v_{12} = (598.12 + 396)\hat i + (363.7 - 410)\hat j$

$v_{12} =994.12\hat i -46.3 \hat j$

now the distance between them is given as

$d = v* t$

$d = (994.12 \hat i - 46.3 \hat j)* 3$

$d = 2982.36\hat i - 138.9\hat j$

so the magnitude of the distance is given as

$d = \sqrt{2982.36^2 + 138.9^2}$

$d = 2985.6$ miles

so the distance between them is 2985.6 miles

5 0

2 years ago

Read 2 more answers

What will be the change in momentum caused by a net force of 120N acting on an object for 2 seconds?

Vinvika [58]

The change in momentum is 240 kgm/s

<u>Explanation:</u>

Given:

Force, F = 120N

Time, dt = 2 sec

Change in momentum, dP = ?

We know,

$F = \frac{dP}{dt}$

On substituting the value we get:

$120 = \frac{dP}{2}\\ \\dP = 240 kgm/s$

Therefore, change in momentum is 240 kgm/s

8 0

3 years ago