Explanation:
Hole. Hole. Different notes can be played on the flute by blocking holes. ...
Drum skin. Drum skin. Hitting the bongo drum makes its tight elastic skin vibrate.
String. String. ...
Sound. hole. ...
Bow. Bow.
Answer:
0.5849Weber
Explanation:
The formula for calculating the magnetic flus is expressed as:

Given
The magnitude of the magnetic field B = 3.35T
Area of the loop = πr² = 3.14(0.24)² = 0.180864m²
angle of the wire loop θ = 15.1°
Substitute the given values into the formula:

Hence the magnetic flux Φ through the loop is 0.5849Weber
Answer:
-387883.3 m/s²
0.000286168546055 seconds
Explanation:
t = Time taken
u = Initial velocity = 370 m/s
v = Final velocity = 259 m/s
s = Displacement = 9 cm
a = Acceleration

The acceleration of the bullet is -387883.3 m/s²

The time taken is 0.000286168546055 seconds
Answer:
1/f = 1/i + 1/o thin lens equation
1/i = 1/f - 1/o
i = o * f / ( o - f) = 50 * (-20) / (50 - (-20)) = -14.3 cm
The final image is erect and 14.3 cm behind the curved surface
M = -o / i = 14.3 / 50 = .29 magnificaton of object
S = .29 * 25 cm = 7.1 cm appearance of bird in mirror (height)
Answer:

Explanation:
Newton's 2nd Law relates the net force <em>F</em> on an object of mass <em>m </em>with the acceleration <em>a</em> it experiments by <em>F=ma.</em> In our case the net force is the friction force, since it's the only one the skier is experimenting horizontally and the vertical ones cancel out since he's not moving in that direction. Our acceleration then will be:

Also, acceleration is defined by the change of velocity
in a given time t, so we have:

Since we want the change in velocity, <em>mixing both equations</em> we conclude that:

Which for our values means:
