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horsena [70]
3 years ago
6

Match the sentences in Column A based on whether they describe radio waves, visible light waves, or both (Column B). Column A 1.

They’re invisible. : They’re invisible. 2. They have colors. : They have colors. 3. They’re used to learn about dust and gas clouds. : They’re used to learn about dust and gas clouds. 4. They can travel in a vacuum. : They can travel in a vacuum. 5. They’re used to find the temperature of stars. : They’re used to find the temperature of stars. 6. They have energy. : They have energy.
Physics
2 answers:
Andrew [12]3 years ago
8 0
<span>1. They’re invisible - RADIO WAVES

2. They have colors. - VISIBLE LIGHT WAVES

3. They’re used to learn about dust and gas clouds. - BOTH

4. They can travel in a vacuum. </span> - BOTH<span>

5. They’re used to find the temperature of stars. </span>- VISIBLE LIGHT WAVES<span>

 6. They have energy. </span> - BOTH
vovikov84 [41]3 years ago
5 0

Answer:

1. They’re invisible - Radio waves

2. They have colors - Visible

3. They’re used to learn about dust and gas clouds. - Both

4. They can travel in a vacuum. - Both

5. They’re used to find the temperature of stars. - Visible

6. They have energy. - Both

Explanation:

The magnetic spectrum consists invisible and visible part of the spectrum. The invisible part consists of radio waves. These are waves used for radios, tvs, and cellphone communications. They satisfy all the properties of transverse waves.

The visible part comes from light. This is the part that is visible to the naked eye. Examples are ultraviolet rays, the sun, neon lights etc. To determine how hot something is, the visible portion is used. The brighter the object, the hotter it is.  Thus, the brightness of the stars can be determined by the color of the light emitted. The visible rays satisfy all the properties of transverse waves. However, light is considered a dual nature - it has wave and electron-like properties.

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Initial height of platform is 15.87m or 16m.

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3 years ago
Two identical loudspeakers are placed on a wall 1.00 m apart. A listener stands 4.00 m from the wall directly in front of one of
natita [175]

Answer:

The phase difference is 0.659 rad.

Explanation:

Given that,

Distance between two identical loudspeakers d= 1.00  m

Distance between speakers and listener r= 4.00 m

Frequency = 300 Hz

Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer

We need to calculate the r'

Using Pythagorean theorem

r'=\sqrt{d^2+r^2}

Where, d = distance between two identical loudspeakers

r = distance between speakers and listener

Put the value into the formula

r'=\sqrt{(1.00)^2+(4.00)^2}

r'=\sqrt{1.00+16.00}

r'=4.12\ m

We need to calculate the path difference

Using formula of path difference

|r'-r|=4.12-4.00

|r'-r|=0.12\ m

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{v}{f}

Where, v = speed of sound

f = frequency

Put the value into the formula

\lambda=\dfrac{343}{300}

\lambda=1.143\ m

We need to calculate the phase difference

Using formula of phase difference

\phi=\dfrac{2\pi\times|r'-r| }{\lambda}

\phi=\dfrac{2\pi\times0.12}{1.143}

\phi=0.659\ rad

Hence, The phase difference is 0.659 rad.

7 0
3 years ago
A driver in a 2000 kg Porsche wishes to pass to pass a slow-moving school bus on a four-lane road. What is the average power in
Kryger [21]

The average power is 3.0\cdot 10^6 W

Explanation:

First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:

W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2

where :

K_f = \frac{1}{2}mv^2 is the final kinetic energy of the car, with

m = 2000 kg is the mass of the car

v = 60 m/s is the final speed of the car

K_i = \frac{1}{2}mu^2 is the initial kinetic energy of the car, with

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Soolving:

W=\frac{1}{2}(2000)(60)^2 - \frac{1}{2}(2000)(30)^2=2.7\cdot 10^6 J

Now we can find the power required for the acceleration, which is given by

P=\frac{W}{t}

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Solving:

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Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

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