What are the physics

The photo shows a clay pot being made on a spinning potter's wheel. What

juin [17]

Answer:

A

Explanation:

Shape the pot so that it has a wider bottom

4 0

3 years ago

Block A, with a mass of 4 kg, is moving with a speed of 2 m/s while Block B, with a mass of 8.4 kg, is moving in the opposite di

dybincka [34]

Answer:

The center of mass move with the velocity of -3.487 m/s.

Explanation:

Given values of block A.

Mass of block A, (M1) = 4 kg

Speed of block A, (V1) = 2 m/s

Given values of block B.

Mass of block B, (M2) = 8.4 kg

Speed of block B, (V2) = -6.1 m/s

Below is the formula to find the velocity of center of mass.

$Velocity = \frac{M1V1 + M2V2}{M1 + M2} \\$

$= \frac{4 \times 2 + 8.4 \times (-6.1) }{4 + 8.4} \\$

$= \frac{- 43.24}{12.4}\\$

$= - 3.487 m/s$

7 0

3 years ago

Ethan is using a machine to mix cement. The work input is 10 and the work output is 8. What is the efficiency of the

Arturiano [62]

Efficiency or $\eta$ is calculated by formula: $\eta=\frac{W_{output}}{W_{input}}$ where $\eta\leq1$ also efficiency has no unit.

Now put in the data and calculate the efficiency.

$\eta=\frac{8}{10}=\boxed{0.8}$

The efficiency of the machine is 0.8

If you want to get percentage just multiply by 100 and you get 80%

Hope this helps.

r3t40

4 0

3 years ago

An object of volume 0.0004m^3 and density 6000kg/m^3 is immersed inside a fluid of density 5000kg/m^3. The force exerted by the

FromTheMoon [43]

We have that the density of the fluid is

$\rho_f=178.57 kg/m3$

From the question we are told that

object of volume 0.0004m^3

density 6000kg/m^3

fluid of density 5000kg/m^3.

Force F=0.7N

Generally the equation for the Force is mathematically given as

$F= v*\rho_f*g\\\\0.7= 0.0004*\rho_f*9.8\\\\\rho_f=\frac{0.7}{0.0004*9.8}$

$\rho_f=178.57 kg/m3$

For more information on this visit

brainly.com/question/13338592?referrer=searchResults

8 0

3 years ago

Grain is pouring into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against each ot

jolli1 [7]

Answer:

The electric force between them if the pieces of grain are 2 cm apart is $3.15\times 10^{-11}\textrm{ N}$ .

Explanation:

Given:

Charge on one grain, $Q_{1}=6\times 10^{-10}\textrm{ C}$

Charge on another grain, $Q_{2}=2.3\times 10^{-15}\textrm{ C}$

Separation between them, $d=2\textrm{ cm}=0.02\textrm{ m}$

Electric force acting between two charges $Q_{1}\textrm{ and }Q_{2}$ separated by a distance $d$ is given as:

$F_{elec}=\frac{kQ_{1}Q_{2}}{d^2}$

Where, $k$ is Coulomb's constant equal to $9\times 10^9\textrm{ }Nm^2/C^2$ .

Now, plug in all the values and solve for $F{elec}$ .

$F{elec}=\frac{9\times 10^9\times 6.0\times 10^{-10}\times 2.3\times 10^{-15}}{(0.02)^2}\\\\F_{elec}=3.15\times 10^{-11}\textrm{ N}$

Therefore, the electric force between them if the pieces of grain are 2 cm apart is $3.15\times 10^{-11}\textrm{ N}$ .

3 0

3 years ago