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4 years ago

If an element has 1 valence electrons, how many dots will be in the elements dot diagram?

2 answers:

4 0

The answer is one dot.

The number of dots an element has represented in the diagram, indicates how many valence eletrons( which is the number of electrons in the most exterior energy level of an atom or ion) the element has. So, 1 valence eletron equals one dot.

Stells [14]4 years ago

3 0

There should only be one dot in the elements dot diagram.

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Atoms are the <br> piece of an

rosijanka [135]

Answer:

Our current model of the atom can be broken down into three constituents parts – protons, neutron, and electrons. Each of these parts has an associated charge, with protons carrying a positive charge, electrons having a negative charge, and neutrons possessing no net charge.

7 0

3 years ago

Gina made 9{,}350 \text{ mL}9,350 mL9, comma, 350, space, m, L of chicken noodle soup. She packed 1.8 \text{ L}1.8 L1, point, 8,

RoseWind [281]

Answer:

$7,550\ mL$

Explanation:

Remember that

$1\ L=1,000\ mL$

To convert L to mL multiply by 1,000

we know that

Gina made 9,350 mL

She packed 1.8 L of the soup in her kids' lunches

She froze the rest of the soup

step 1

Convert L to mL

$1.8\ L=1.8(1,000)=1,800\ mL$

step 2

To find out how many milliliters of soup did Gina have left to freeze, subtract 1,800 mL from 9,350 mL

$9,350-1,800=7,550\ mL$

5 0

4 years ago

Read 2 more answers

How do the key results indicate

Lena [83]

The key results explain how you'll achieve a certain goal. They have to be quantitative, but always measurable in terms of their progress. This has to be considered when it comes to key results, because only results count for each milestone on the way to achieving the goal in question.

7 0

4 years ago

does anyone know how to find the electron configuration of an element without using a periodic table?? group and period is alrea

snow_lady [41]

For that you have to use the Aufbau principle

For example, writing the electronic configuration of Fe(28)

I recommend that you memorize the aufbau principle. Once you learn it, you don’t need anything else except the atomic number of the element to write it’s electronic configuration.

8 0

2 years ago

Read 2 more answers

A 35.161 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis ap

xxMikexx [17]

Answer:

The empirical formulae is C6H12S02

Explanation:

1. First we need to obtain the mass of each element in the sample and compound formed

Carbon = (62.637 mg * 12.011 g/mol / 44.009 g/mol) = 17.094 mg of Carbon

Hydrogen = ( 25.641 mg * (2 *1..008 g/mol) / 18.015 g/mol) = 2.869 mg of Hydrogen

Sulphur = (13.54 mg * 32.066 g/mol / 64.066 g/mol) = 6.777 mg of Sulphur

2. Next is to determine the percentage composition. Here we divide the respective mass by the mass of the sample

Carbon = 17.094 / 35.161 * 100 = 48.62 %

Hydrogen = 2.869/ 35.161 *100 = 8.16 %

Sulphur = 6.777/ 31.321 *100 = 21.64 %

Oxygen = (100 - (48.62 + 8.16 + 21.64)) = 21.58 %

3. Next is to divide the mass assuming there are 100 mg by the respective atomic masses to obtain the number of moles

Carbon = 48.62 / 12.011 = 4.048 mol

Hydrogen = 8.16 / 1.008 = 8.095 mol

Sulphur = 21.64 / 32.066 = 0.675 mol

Oxygen = 21.58 / 16.000 = 1.348 mol

Next is to divide by the smallest value

Carbon = 4.048/ 0.675 =5.997 = 6

Hydrogen = 8.095 / 0.675 =11.993 =12

Sulphur = 0.675/ 0.675 = 1

Oxygen = 1.348 / 0.675 = 1.997 = 2

So therefore the empirical formulae of the sample is C6H12SO2

7 0

4 years ago