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adoni [48]
3 years ago
10

Determine the molarity of a solution prepared by dissolving 141.6 g of citric acid, C3H5O(COOH)3, in 3500.0 mL of water ?

Chemistry
2 answers:
Usimov [2.4K]3 years ago
6 0

Answer:

0.21M of C3H5O(COOH)3

Explanation:

Molarity = no of mole/ volume of solution

Molar mass of C3H5O (COOH)3 = 192.12g

No of mole of C3H5O (COOH)3 = 141.6/192.12 = 0.74mol

1000mL = 1L

3500mL = 3.5L

Molarity = 0.74/ 3.5 = 0.21M of C3H5O (COOH)3

dangina [55]3 years ago
6 0

Answer:

0.2M

Explanation:

The molarity of a solution is given by;

M = number of moles / volume

Number of moles = mass/molar mass

Mass of Citric acid = 141.6g

Molar mass of citric acid = (6×12)+(8×1)+(7×16)

= 72+8+112=192g/mol

Number of moles of citric acid=141.6/192=0.74mol

Volume = 3500.0 mL = (3500/1000)L=3.5L

Molarity of the solution = 0.74mol/3.5L=0.2mol/L

Therefore, 0.2mol/L or 0.2M concentration is prepared by dissolving 141.6 g of citric acid, C3H5O(COOH)3, in 3500.0 mL of water

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3 years ago
It is required to prepare 1250 kg of a solution composed of 12 wt.% ethanol and 88 wt.% water. Two solutions are available, the
bekas [8.4K]

Answer:

437.5 kg of first solution and 812.5 kg of second solution should be mixed to get desired solution.

Explanation:

Let the mass of the first solution be x and second solution be y.

Amount solution required = 1250 kg

x + y = 1250 kg....[1]

Percentage of ethanol in required solution = 12% of 1250 kg

Percentage of ethanol in solution-1 = 5% of x

Percentage of ethanol in required solution = 25% of y

5% of x +  25% of y =12% of 1250 kg

\frac{5}{100}\times x+\frac{25}{100}y=\frac{12}{100}\times 1250 kg

x + 5y = 3000 kg...[2]

Solving [1] and [2] we :

x = 437.5 kg   , y =  812.5 kg

437.5 kg of first solution and 812.5 kg of second solution should be mixed to get desired solution.

8 0
3 years ago
What is the molecular formula of a compound if its emprical formula is NO2 and its molar mass is 138.02 g/mole
Ratling [72]

Answer:

N₃O₆  

Step-by-step explanation:

Data:

EF = NO₂

MM = 138.02 g/mol

Calculations:

EF Mass = (14.01 + 32.00) u

EF Mass = 46.01 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

  n = MF Mass/EF Mass  

  n = 138.02 u/46.01 u  

  n = 3.000 ≈3

MF = (NO₂)₃

MF = N₃O₆

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Answer:

B. Changes in the Moon's visibility.

Explanation:

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