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3 years ago

2H2(g) + O2(g) mc001-1.jpg 2H2O(g)

Chemistry

2 answers:

Aleks [24]3 years ago

6 0

The answer is a) by increasing the temperature of the reactants.

Lesechka [4]3 years ago

6 0

Answer:

Explanation:

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A gold nugget has a density of 38.6g/cm3 and a mass of 270.2. what is its volume?

aivan3 [116]

Density is given by the equation D=m/V, were D is density, m is mass in grams, and V is volume in cubic centimeters.

In this problem, we have density and we have mass so we can plug into the equation and solve for V.

38.6=270.2/V

<em>*Multiply both sides by V*</em>

38.6V=270.2

<em>*Divide both sides by 38.6*</em>

V=7

The volume of the gold nugget is 7cm3.

Hope this helps!!

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3 years ago

Read 2 more answers

. Using the pH scale below what would be the pH value of an Acid? *

earnstyle [38]

Answer : The pH value of an acid is below 7.

Explanation :

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

Mathematically,

$pH=-\log [H^+]$

When the pH less than 7 then the solution is acidic and the concentration of hydrogen ion is greater than hydroxide ion.

When the pH more than 7 then the solution is basic and the concentration of hydrogen ion is less than hydroxide ion.

When the pH is equal to 7 then the solution is neutral and the concentration of hydrogen ion is equal to the hydroxide ion.

Hence, the pH value of an acid is below 7.

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3 years ago

A cook places a pan of food on a hot stove and leaves it there. When the food is just about done cooking, which of the following

rjkz [21]

Answer:

The pan will be the same temperature as the stove.

Explanation:

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3 years ago

Find out no. of moles present is 72 gm of water?

Alona [7]

72g H2O x 1 mol H2O/18.02g H2O = 3.99 mol H2O

8 0

3 years ago

When a 1.00 L sample of water from the surface of the Dead Sea (which is more than 400 meters below sea level and much saltier t

Harlamova29_29 [7]

Answer: Molarity of $MgCl_2$ in the original sample was 1.96M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{\text{no of moles}}{\text{Volume in L}}$

${\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{186g}{95g/mol}=1.96$

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{1.96}{1.00L}$

$Molarity=1.96mol/L$

Thus molarity of $MgCl_2$ in the original sample was 1.96M

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3 years ago