Answer: The value of equilibrium constant for reaction is,
Explanation:
The given chemical equations are:
(1)
;
(2)
; 
Now we have to calculate the equilibrium constant for chemical equation as:
; 
We are reversing reaction 2 and multiplying reaction 2 by 2 and then adding both reaction, we get the final reaction.
The equilibrium constant for the reverse reaction will be the reciprocal of that reaction.
If the equation is multiplied by a factor of '2', the equilibrium constant of that reaction will be the square of the equilibrium constant.
If we are adding equations then the equilibrium constants will be multiplied.
The value of equilibrium constant for reaction is:

Now put all the given values in this expression, we get:


Hence, the value of equilibrium constant for reaction is,
-Just look up “H2O lewis structure
-1.5
-Don’t know the VSEPR
-Polar Covalent
-Again, don’t know VSEPR
-Just look up H2O molecule
Answer:
C. 1-ethyl, 3-methylcyclohexane
(Photo for proof at the bottom.)
Explanation:
The 1-ethyl is because you start numbering from the longest branch, towards the next closest branch. Prefix "eth-" means two, there are 2 carbons in the longest branch. 3-methyl is because the next branch is at number 3, and prefix "meth-" means 1, there is 1 carbon in that chain. "Cyclo" in cyclohexane means the skeletal model is shaped like a ring, and the "hexane" means there are 6 carbons in the ring. Prefix "hex" means 6.
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The only exception of calculating mechanical advantage is by multiplying resistance force by effort force. For example, in calculating the mechanical advantage of a lever, we consider its output and input forces. The equation would now be as follows:
Mechanical advantage = output force / input force
Answer:
Rate of reaction = -d[D] / 2dt = -d[E]/ 3dt = -d[F]/dt = d[G]/2dt = d[H]/dt
The concentration of H is increasing, half as fast as D decreases: 0.05 mol L–1.s–1
E decreseas 3/2 as fast as G increases = 0.30 M/s
Explanation:
Rate of reaction = -d[D] / 2dt = -d[E]/ 3dt = -d[F]/dt = d[G]/2dt = d[H]/dt
When the concentration of D is decreasing by 0.10 M/s, how fast is the concentration of H increasing:
Given data = d[D]/dt = 0.10 M/s
-d[D] / 2dt = d[H]/dt
d[H]/dt = 0.05 M/s
The concentration of H is increasing, half as fast as D decreases: 0.05 mol L–1.s–1
When the concentration of G is increasing by 0.20 M/s, how fast is the concentration of E decreasing:
d[G] / 2dt = -d[H]/3dt
E decreseas 3/2 as fast as G increases = 0.30 M/s