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aliina [53]
3 years ago
8

You are in Paris and want to buy peaches for lunch. The sign on the fruit stand indicates that peaches cost 11.50 euros per kilo

gram. On that day, the euro is 1.25 dollars. How much would a pound of peaches cost in dollars?
Chemistry
1 answer:
nydimaria [60]3 years ago
4 0

Answer:

1 lb of peaches costs 6.52 dollars

Explanation:

You can solve this problem using the rule of three.

You might want to follow these steps:

1. Analyze the giving data

2. Organize it and write the proportions  

3. Clear the x value

4. Solve by multiplying or dividing

Now for the exercise:

Data:

$11.50 euros per 1 kg

1 euro is 1.25 dollars

Conversion factor 1 kg = 2.02462 lb

The problem is asking how much will be the cost in dollars to buy 1 lb of peaches? As you can see! You need to change the units to modify the data information.

Remember that 1 kg = 2.02462 lb

First change the kg to lb, in this case use directly the conversion factor:

2.02462 lb =  1 kg

Now you want to know the cost of 1 lb

1 lb               ---->   x euros?

2.20462 lb -----> 11.50 euros

Clear the incognite x euros?

1 lb (11.50 euros) =   x euros? (2.20462 lb)

x euros? = 1 lb (11.50 euros) / 2.20462 lb = 5.22 euros

The cost of 1 lb of peaches will be 5.22 euros, but you need to know the cost in dollars.

You will need to write another proportion:

1 euro          -----> 1.25 dollars

5.216 euros -----> x dollars?

Now solve for incognite x dollars?

1 euro (x dollars?) = 1.25 dollars (5.216 euros)

x dollars? = 1.25 dollars (5.216 euros)/(1 euro) = 6.52 dollars

Now you that 1 lb of peaches costs 6.52 dollars

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The answer is more protons than electrons.
5 0
3 years ago
A fine of 50.0 mL of 0.0900 M CaCl2 reacts with excess sodium carbonate to give 0.366 g of calcium carbonate precipitate. What i
In-s [12.5K]

Answer:

81.26% is the percent yield

Explanation:

Based on the reaction:

CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃

<em>Where 1 mole of CaCl₂ in excess of sodium carbonate produces 1 mole of calcium carbonate.</em>

<em />

To solve this question we must find the moles of CaCl2 added = Moles CaCO₃ produced (Theoretical yield). The percent yield is:

Actual yield (0.366g) / Theoretical yield * 100

<em>Moles CaCl₂ = Moles CaCO₃:</em>

0.0500L * (0.0900moles / L) = 0.00450 moles of CaCO₃

<em>Theoretical mass -Molar mass CaCO₃ = 100.09g/mol-:</em>

0.00450 moles of CaCO₃ * (100.09g / mol) = 0.450g of CaCO₃

Percent yield = 0.366g / 0.450g * 100

81.26% is the percent yield

3 0
3 years ago
Question 3) A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of
Masja [62]

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

<u>Explanation:</u>

We have the chemical equation,

HF (aq)+NaOH(aq)->NaF(aq)+H2O

To find how many moles have been used in this

c= n/V=> n= c.V

nHF=0.250 M⋅1.5 L=0.375 moles HF

Simillarly

nF=0.250 M⋅1.5 L=0.375 moles F

nHF=0.375 moles - 0.250 moles=0.125 moles

nF=0.375 moles+0.250 moles=0.625 moles

[HF]=0.125 moles/1.5 L=0.0834 M

[F−]=0.625 moles/1.5 L=0.4167 M

To determine the problem using the Henderson - Hasselbalch equation

pH=pKa+log ([conjugate base/[weak acid])

Find the value of Ka

pKa=−log(Ka)

pH=−log(Ka) +log([F−]/[HF]

pH= -log(3.5 x 10 ^4)+log(0.4167 M/0.0834 M)

pH=-log(3.5 x 10 ^4)+log(4.996)

pH= -4.54+0.698

pH=-(-3.84)

pH=3.84

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

5 0
3 years ago
Calculate the number of atoms in 2 mol of sulfur dioxide (SO2).
Alex17521 [72]
Two moles of SO2 means 1.204x10^24 molecules, since there are 3 atoms in one molecule, multiply 1.204 x10^24 by 3 and you get 3.612x10^24.
7 0
3 years ago
12.
Veronika [31]

Answer:

Nonbonding pairs of electrons.

Explanation:

Both oxygen atoms in the diatomic molecule have two nonbonding pairs. This results in the oxygen molecule having a planar geometric shape. This is because nonbonding pairs repel each other are significant in determining the shape of a molecule.

3 0
3 years ago
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