Answer:
The answer is below
Step-by-step explanation:
Let S denote syntax errors and L denote logic errors.
Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56
a) The probability a program contains both error types = P(S ∩ L)
The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L) - P(L) = 56% - 47% = 9%
The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%
b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
c) The probability a program has logic errors, but not syntax errors = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
Answer:
10
Step-by-step explanation:
say x=0
then y would be 1
increasing x by 5 makes x=5
and then 5 x 2 + 1=11
so y went from 1-11(difference of 10) with the variation
so the answer is 10
It’s the second option, (x,y) —> (3x,3y) since you have to multiply each coordinate by a certain number called the scale factor (in this case, it’s 3)
The first option won’t work because the scale factor has to be same for both coordinates. The third option is a translation, and the fourth won’t work either because you have to multiply each coordinate by the same variable.
Wx+yz=bc
minus wx on both sides
yz=bc-wx
dividing 'y' on both sides
Hence,
z=(bc-wx)/y
Here is what you need.
Hope it helped
