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Aneli [31]
3 years ago
5

Compare the series circuit with one light bulb and a series circuit with two light bulbs. When you created a series circuit with

only one light bulb, did the light bulb illuminate the same as the series circuit with two light bulbs?
Chemistry
1 answer:
Lena [83]3 years ago
7 0
Yes it should, not 100% possitive though
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What is the ratio of the side lengths on polygon FGHIJ to the corresponding side lengths on polygon ABCDE? Enter the ratio in th
alukav5142 [94]

Explanation:

this is the exact answer!!

7 0
3 years ago
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Calculate the hydroxide ion concentration [oh-] for human urine (ph = 6.2). notice this is about hydroxide.
igomit [66]

[OH⁻] = 1.6 × 10⁻⁸ mol / dm³

<h3>Explanation</h3>

By definition, [\text{H}^{+}] = 10^{-\text{pH}}, where [\text{H}^{+}] is the concentration of proton in the solution.

pH = 6.2 for this solution. As a result, [\text{H}^{+} = 10^{-6.2} = 6.31 \times 10^{-7} \; \text{mol} \cdot \text{dm}^{-3}.

[\text{H}^{+}] \cdot [\text{OH}^{-}] = \text{K}_w, where [\text{OH}^{-}] the concentration of hydroxide ions and \text{K}_w is the dissociation constant of water.

\text{K}_w = 10^{-14} \; \text{mol}\cdot \text{dm}^{-3} at 0.10 MPa and 25 °C. As a result, [\text{OH}^{-}] = \text{K}_w / [\text{H}^{+}] = 10^{14} / (6.31 \times 10^{-7}) = 1.6 \times 10^{-8} \; \text{mol}\cdot \text{dm}^{-3}.

5 0
3 years ago
What is the mass of of 3.20 X 10^23 particles of Co2?​
vitfil [10]

Answer:

Mass = 23.36 g

Explanation:

Given data:

Number of particles of CO₂ = 3.20 ×10²³

Mass of  CO₂ = ?

Solution:

1 mole contain 6.022×`10²³ particles,

3.20 ×10²³ particles  × 1 mol / 6.022×`10²³ particles

0.531 mol

Mass of CO₂:

Mass = number of moles × molar mass

Molar mass = 44 g/mol

Mass =  0.531 mol× 44 g/mol

Mass = 23.36 g

6 0
3 years ago
A gas mixture being used to simulate the atmosphere of another planet at 23°c consists of 337 mg of methane, 148 mg of argon, an
Karolina [17]

The total pressure of the mixture is 65.5 kPa.

According to Dalton's Law of Partial Pressure,

The partial pressure of gas = Mole fraction of gas × Total pressure

Total Pressure = Sum of all the gases partial pressures

The number of moles of methane is,

Moles \:  of \: methane  \: (16 g/mol) =  337 \: mg  \times  \frac{1 g}{1000 mg} \times  \frac{ 1 mol}{16 g }

= 0.021 mols

The moles of methane are 0.021 mols.

The number of moles of the argon,

Moles \:  of \: argon (40 g/mol) = 148 \:  mg  \times  \frac{  1 g}{1000 mg } \times  \frac{  1 mol}{40 g}

= 0.003 mols

The number of moles of argon is 0.003 mols.

The number of moles of nitrogen is,

Moles  \: of \: nitrogen (28 g/mol) = 296 \:  mg  \times  \frac{ 1 g}{1000 mg}  \times  \frac{  1 mol/}{28 g}

= 0.010 mols

The number of moles of nitrogen is 0.010 mols.

The total number of moles is,

= 0.021 + 0.003 + 0.010

= 0.034 mols

Mole \:  fraction =  \frac{ Moles \:  of \:  solute }{Total \:  number  \: of  \:  moles  \: of  \: soulte \:  and \:  solvent}

= \frac{  0.010 }{ 0.034}

= 0.29

0.29 \: P _{total} = 19 \:  kPa

P _{total} =  \frac{ 19  \: kPa }{0.29}

= 65.5 kPa

Therefore, the total pressure of the mixture is 65.5 kPa.

To know more about Dalton's law, refer to the below link:

brainly.com/question/14119417

#SPJ4

6 0
1 year ago
4. Again, have someone hold the mirror for you, slowly move at least 3 m away
faltersainse [42]
Closer is bigger................
8 0
3 years ago
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