Answer:
pH= 11.5
Explanation:
To the calculation of the <u>pH value</u>, we need to write the ionization equation first. Then using the <u>ICE table</u> and the information given by the problem we can set up the problem:

I 1.1 M Zero Zero
C -X +X +X
E 1.1-X X X
As next step, using the <u>equilibrium expression</u> for Kb we can replace the terms find in the ICE table and then <u>solve for X</u>, so:
![Kb=\frac{[C_4H_4N_2O_3NH_3^+][OH^-]}{[C_4H_4N_3O_3NH_2]}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BC_4H_4N_2O_3NH_3%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BC_4H_4N_3O_3NH_2%5D%7D)
![9.2x10^-^6=\frac{[X][X]}{[1.1-X]}](https://tex.z-dn.net/?f=9.2x10%5E-%5E6%3D%5Cfrac%7B%5BX%5D%5BX%5D%7D%7B%5B1.1-X%5D%7D)

![(9.2x10^-^6)*[1.1-X]=X^2](https://tex.z-dn.net/?f=%289.2x10%5E-%5E6%29%2A%5B1.1-X%5D%3DX%5E2)


With the value of X we can find the <u>pOH</u> (lets remember that X<u> is the concentration of OH-</u>), so:


Finally, we can find the <u>pH value</u> with the equation:




<u>The 1.1 M allantoin solution have a pH value of 11.5</u>
Answer:
Density stays the same
Explanation:
The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.
D. impermeable rocks
Explanation:
Impermeable rocks is the factor among the give choices that will increase the amount of water runoff on the surface.
Surface run-off is liquid water that flows and moves on the earth surface.
- An impermeable rock is a rock that lacks porosity and permeability.
- Porosity is the amount or percentage of void spaces in rock.
- Permeability is the inter-connectivity of the pores.
- When a rock is impermeable, it will not allow water to infiltrate.
learn more:
Biogeochemical cycle brainly.com/question/3509510
#learnwithBrainly
Answer: It is a gas
Explanation:
The most unique thing about nitric oxide being a neurotransmitter is that it is the only neurotransmitter which is in gaseous form.
Nitric oxide is small gaseous molecules which is synthesized by the de novo process in the neuronal tissue.
It can diffuse by plasma membrane.
It diffuses out of the postsynaptic neurons and acts on the neighboring neurons and presynaptic terminals to assist the generation of the Long Term potentiation.