Answer:
Thus, the order of the reaction is 2.
The rate constant of the graph which is :- 2.00 M⁻¹s⁻¹
Explanation:
The kinetics of a reaction can be known graphically by plotting the concentration vs time experimental data on a sheet of graph.
The concentration vs time graph of zero order reactions is linear with negative slope.
The concentration vs time graph for a first order reactions is a exponential curve. For first order kinetics the graph between the natural logarithm of the concentration vs time comes out to be a straight graph with negative slope.
The concentration vs time graph for a second order reaction is a hyberbolic curve. Also, for second order kinetics the graph between the reciprocal of the concentration vs time comes out to be a straight graph with positive slope.
Considering the question,
A plot of 1/[NOBr] vs time give a straight line with a slope of 2.00 M⁻¹s⁻¹.
<u>Thus, the order of the reaction is 2.</u>
<u>Also, slope is the rate constant of the graph which is :- 2.00 M⁻¹s⁻¹</u>
Answer:
B. A rate constant
Explanation:
The mathematical expression of rate law is given below,
Rate = K[A]m[B]n
This rate law show the relationship between the rate of chemical reaction and concentration of reactants.
In given equation [A] and [B] are molar concentration of reactants while K represent rate constant.
The value of K is specific for particular reaction at particular temperature,
m and n are represent exponents and determine experimentally. The value of K is not depend upon the concentrations of reactant but depend upon the surface area and temperature
Answer:
0.726 mol·L⁻¹
Step-by-step explanation:
c = moles/litres
=====
Moles = 29.8 × 1/342.30
Moles = 0.087 06 mol
=====
Litres = 120 × 1/1000
Litres = 0.120 L
=====
c = 0.087 06/0.120
c = 0.725 mol·L⁻¹
Both trials of 1.2 g and 1.6 g will have the same mass percent of water because the ratio of the salt to the water of hydration is always constant for any hydrated salt.
<h3>Water of hydration</h3>
For every hydrated salt, the ratio of the salt to the water of hydration remains constant irrespective of the amount of salt taken for experimental analysis.
For example, assuming the mass percent of water in 10g of a hydrated salt is 40%, if 100g of the same salt is taken, the mass percent will remain 40%.
More on water of hydration can be found here: brainly.com/question/11202174
Answer:
No
Explanation:
If you heat the air inside a rigid, sealed container, then you are keeping it's mass and volume constant.
Then, Pressure of the container is directly proportional to the temperature.
Gay-Lussac's Law: This law states that the pressure of a given amount of gas when at constant volume is directly proportional to gas's absolute temperature in Kelvin.
So, if Kelvin temperature doubles, the air pressure in the container will also double.
The relationship between Celsius temperature and Kelvin temperature is not linear.
If 
becomes 
, then 
will become 
.
i.e, it is increasing for sure, but doesn't double.
