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Sveta_85 [38]
3 years ago
13

What is the name of the base represented by the formula NH4OH

Chemistry
2 answers:
romanna [79]3 years ago
8 0

Answer:

The answer is (a); Ammonium hydroxide

Explanation:

Ammonium hydroxide is represented as NH4OH.

Ammonium hydroxide is an alkali (base) formed when ammonia (NH3) is dissolved in water (H2O).

NH3 + H2O ↔ NH4OH

As seen above, the reaction is reversible. Ammonia itself is a base, dissolving it in water makes up this compound.

The formula for hydrogen hydroxide (which is commonly known as water) is H2O while the formula for nitrogen hydroxide (which is commonly known as nitric acid) is HNO3.

kotegsom [21]3 years ago
4 0
It's Ammonium hydroxide
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A student measures a volume as 25 ml, wheras the correct volume is 23 mL. What is the percent error?
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the other number is different

Explanation:

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How do you determine the percent yield of a chemical reaction?
valentinak56 [21]

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percentage yield =[ experimental yield / theoretical yield] x 100

Explanation:

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If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + NaI → PbI2 + NaNO3
ss7ja [257]

Answer:- 27.7 grams of PbI_2 are produced.

Solution:- The balanced equation is:

Pb(NO_3)_2+2NaI\rightarrow PbI_2+2NaNO_3

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of Pb(NO_3)_2 = 207.2+2(14.01)+6(16)  = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2 = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})

= 39.0gPbI_2

18.0gNaI(\frac{1molNaI}{149.89gNaI})(\frac{1molPbI_2}{2molNaI})(\frac{461gPbI_2}{1molPbI_2})

= 27.7gPbI_2

From above calculations, NaI gives least amount of PbI_2, so the answer is, 27.7 g of PbI_2 are produced.

8 0
3 years ago
If the sum of the mass of the reactants is 12.5 what would be the sum of the products be? And explain how you know this
Strike441 [17]
If all the reactants will react and become products, the mass will be 12.5 g. Because the mass of the matter amount will not change during the reaction.
7 0
3 years ago
When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot
viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the 'n^{th}' orbit of hydrogen atom.

Formula used :

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number  of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV

Energy of n = 2 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

3 0
3 years ago
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