Explanation:
Net ionic between HCl and the buffer equation
CH3COOH --> acetic acid, CH3COO- acetate , H+ proton from HCl
there is neutralization of the acetate, and an increase in acid
the ionic equation
CH3COO-(aq) + H+(aq) + Cl-(aq) --> CH3COOH(aq) + Cl-(aq)
Net ionic:
CH3COO-(aq) + H+(aq) --> CH3COOH(aq).
Twice as much more will the freezing point of water be lowered in beaker a than in beaker b.
<h3>What determines freezing point?</h3>
A liquid's freezing point rises if the intermolecular interactions between its molecules are strong. The freezing point, however, drops if the molecules of inter - molecular are minimal. The process through which a substance transforms from a liquid into a solid is known as freezing.
<h3>How significant is freezing point?</h3>
Freezing points play a big role in occupational safety. A chemical may perhaps turn harmful if held below its freezing point. A critical safety benchmark for assessing the effects of worker exposure to cold environments is the freezing point.
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Answer:
6.2g of NaBr are produced
Explanation:
The reaction of HBr with NaOH occurs as follows:
HBr + NaOH → NaBr + H2O
<em>Where 1 mole of each reactant produce 1 mole of NaBr</em>
To solve this question we need to find the moles of each reactant using their molar mass. With moles we can find limiting reactant and the moles (And mass) of NaBr produced, as follows:
<em>Moles HBr -Molar mass: 80.9119g/mol)-</em>
4.9g * (1mol/80.9119g) = 0.0606 moles HBr
<em>Moles NaOH -Molar mass: 40g/mol-</em>
3.86g * (1mol/40g) = 0.0965 moles NaOH
As the reaction is 1:1 and the moles of HBr < Moles NaOH, the limiting reactant is HBr and moles of NaBr produced are 0.0606 moles.
The mass of NaBr (Molar mass: 102.894g/mol) is:
0.0606 moles * (102.894g/mol) =
<h3>6.2g of NaBr are produced</h3>
The first diagram is showing carboxylic acid because carboxyl contains a Carbon atom as the central atom bonded with OH group, a double bonded Oxygen, hydrogen ofc, and a lone R group.
2. It is ester group
3. Correct its ether
4. It's the exact diagram for ethyl alcohol, so correct
WOOT WOOOT
Answer: B. you will need 53.2 g Cl2 for complete reaction and will produce 66.7 g of AlCl3.
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.
To calculate the moles, we use the equation:
The balanced reaction is:
2 moles of aluminium react with= 3 moles of chlorine
Thus 0.5 moles of aluminium react with= moles of chlorine
Mass of chlorine=
2 moles of aluminium produce = 2 moles of aluminium chloride
Thus 0.5 moles of aluminium react with= moles of aluminium chloride
Mass of aluminium chloride=
Thus 53.2 g of chlorine is used and 66.7 g of aluminium chloride is produced.