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3 years ago

BC must be with length for this quadrilateral to be a parallelogram?

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

5 0

You need to provide a homie wit some more details lol

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Question. 1 :

vovikov84 [41]

<h3>Answer to Question 1:</h3>

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

<h3>Answer to Question 2 :-</h3>

sin A = 3/4

CosA = ?

TanA = ?

<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

<h3>CosA = Adjacent side/Hypotenuse</h3>

= AB/AC

= √7/4

<h3>TanA= Opp. side/Adjacent side</h3>

=BC/AB

= 3/√7

4 0

2 years ago

Tyler does squats and pushups. He wants to increase the number of each type of exercise by 20% by the end of the month. He curre

Semenov [28]

Answer:

Tyler currently does 40 squats

Step-by-step explanation:

Tyler does squats and pushups.

<u>Currently:</u>

Number of pushups = 25

Number of squats = x

Total number = 25 + x

<u>After increase:</u>

Number of pishups $=25\cdot (1+0.2)=1.2\cdot 25=30$

Number of squats $=x\cdot (1+0.2)=1.2x$

Total number $=30+1.2x$

If Tyler meets his goal, he will do a total of 13 more squats and pushups than he does now, thus

$(30+1.2x)-(25+x)=13\\ \\30+1.2x-25-x=13\\ \\1.2x-x=13-30+25\\ \\0.2x=8\\ \\2x=80\\ \\x=40$

6 0

3 years ago

What is 0.309 in word form

vovikov84 [41]

Point three-hundred and nine

zero point three-hundred and nine

7 0

3 years ago

Read 2 more answers

Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7.

Alecsey [184]

<u><em>Answer:</em></u>

y^2 = 28x

<em><u>Step-by-step explanation:</u></em>

Since the directrix is horizontal, use the equation of a parabola that opens left or right.

(y−k)^2 = 4p(x−h)

Find the vertex.

(0,0)

Find the distance from the focus to the vertex.

p = 7

Substitute in the known values for the variables into the equation

(y−k)^2 = 4p(x−h).

(y−0)^2 = 4(7)(x−0)

Simplify.

7 0

3 years ago

Read 2 more answers

Find the H.C.F of the following expressions.

MAVERICK [17]

Step-by-step explanation:

Hey there!

Please look your required answer in pictures.

<u>Hope</u><u> it</u><u> helps</u><u>!</u>

6 0

3 years ago