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mars1129 [50]
3 years ago
10

When a hot metal cylinder is dropped into a sample of water, the water molecules _____________________ to reach the final temper

ature.
Physics
2 answers:
ASHA 777 [7]3 years ago
5 0

Answer: I believe the answer is speed up.

Explanation: This is because when water heats up the molecules move farther apart from eachother they speed up, eventually causing the water to boil.

Anna11 [10]3 years ago
5 0

Answer:

When a hot metal cylinder is dropped into a sample of water, the water molecules <u>will move with greater speed</u> to reach the final temperature.

Explanation:

As we know that internal energy of the system of gas or any fluid or any matter is only function of its temperature.

Which means if the internal energy of the system is increased then its temperature must have to increase which means the kinetic energy of the molecules of that system will have to increase

So in the given case if hot cylinder is dropped in water then due to energy exchange between cylinder and water the temperature of water will increase and due to this the molecules of water will have more internal energy.

Due to increase in internal energy of molecules of water the kinetic energy of the molecules will increase and this leads to speed up of the water molecules.

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Two microwave signals of nearly equal wavelengths can generate a beat frequency if both are directed onto the same microwave det
alekssr [168]

Answer:

1.5106 cm

Explanation:

The beat frequency is equal to the absolute value of the difference between the frequencies of the two signals:

f_B = |f_1 - f_2|

using the wave equation, we can re-write each frequency as

f=\frac{c}{\lambda}

where c is the speed of light and \lambda is the wavelength. Therefore,

f_B = |\frac{c}{\lambda_1}-\frac{c}{\lambda_2}|

where:

f_B = 140 MHz = 140\cdot 10^6 Hz is the beat frequency

\lambda_1 = 1.50 cm = 0.015 m is the wavelength of the first generator

\lambda_2 is the wavelength of the second generator

We also know that the second generator emits the longer wavelength, so we already know that the term inside the module is positive. Therefore, we can now solve for \lambda_2:

f_B = c(\frac{1}{\lambda_1}-\frac{1}{\lambda_2})\\\lambda_2=(\frac{1}{\lambda_1}-\frac{f_B}{c})^{-1}=(\frac{1}{0.015}-\frac{140\cdot 10^6}{3\cdot 10^8})^{-1}=0.015106 m = 1.5106 cm

4 0
3 years ago
What is the specific heat of silver if the temp ig a 15.4g sample of silver is increased frin 20 degrees celsius to 31.2 degrees
Genrish500 [490]

heat = mass x spec heat x temp rise

40.5=15.4x10^-3xspec heatx11.2

4 0
3 years ago
Consider a rectangular ice floe 5.00 m high, 4.00 m long, and 3.00 m wide. a) What percentage of the ice floe is below the water
artcher [175]

Answer:

(a) 92 %

(b) 6.76 %

Explanation:

length, l = 4 m, height, h = 5 m, width, w = 3 m, density of water = 1000 kg/m^3

density of ice = 920 kg/m^3, density of mercury = 13600 kg/m^3

(a) Let v be the volume of ice below water surface.

By the principle of flotation

Buoyant force = weight of ice block

Volume immersed x density of water x g = Total volume of ice block x density

                                                                      of ice x g

v x 1000 x g = V x 920 x g

v / V = 0.92

% of volume immersed in water = v/V x 100 = 0.92 x 100 = 92 %

(b) Let v be the volume of ice below the mercury.

By the principle of flotation

Buoyant force = weight of ice block

Volume immersed x density of mercury x g = Total volume of ice block x  

                                                                      density of ice x g

v x 13600 x g = V x 920 x g

v / V = 0.0676

% of volume immersed in water = v/V x 100 = 0.0676 x 100 = 6.76 %

4 0
3 years ago
S When an uncharged conducting sphere of radius a is placed at the origin of an x y z coordinate system that lies in an initiall
telo118 [61]

The sphere has a constant potential. It is the electric field.

E = V_{0} = 0

In the sphere, then

E_{x} = 0,  E_{y}=0,   E_{z}=0

Outside the sphere, then

V = V_{0} - E_{0}z + \frac{E_{0}a^{3}z}{(x^{2} +y^{2} + z^{2})^{3/2}   }

The elements of the electric field include

E_{x} =\frac{3E_{0}a^{3}xy}{(x^{2} +y^{2} +z^{2})^{5/2}}\\E_{y} = \frac{3E_{0}a^{3}xz}{(x^{2} +y^{2}+z^{2})^{5/2}}

Which becomes,

=E_{0} (1-\frac{a^{3}}{x^{2} +y^{2}+z^{2})^{3/2}}+\frac{3a^{3}z^{2}}{(x^{2} +y^{2}+z^{2})^{5/2}})

<h3>In a consistent electric field, is force constant?</h3>

Similar to an ordinary object in the uniform gravitational field near the Earth's surface, a charged item in a uniform electric field experiences a constant force and consequently experiences a uniform acceleration. The vector cross product of p and E determines the torque's direction.

If the charge is positive, the force either moves in the same direction as E or in the opposite direction (if charge is negative).

A torque is experienced by an electric dipole (p) in an even electric field (E). The vector cross product of p and E determines the torque's direction.

To learn more about uniform electric field, visit

brainly.com/question/17426130

#SPJ4

5 0
2 years ago
The description for a certain brand of house paint claims a coverage of 475 ft²/gal.
AlexFokin [52]

Answer:

(a) 11.66 square meters per liter

(b) 11657.8 per meters

(c) 0.00211 gal per square feet

Explanation:

(a) 475ft^2/gal = 475ft^2/gal × (1m/3.2808ft)^2 × 1gal/3.7854L = 11.66m^2/L

(b) 475ft^2/gal = 475ft^2/gal × (1m/3.2808ft)^2 × 264.17gal/1m^3 = 11657.8/m

(c) Inverse of 475ft^2/gal = 1/475ft^3/gal = 0.00211gal/ft^3

8 0
3 years ago
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