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3 years ago

Why is evidence good for practice

Physics

2 answers:

posledela3 years ago

8 0

Answer:

HEYO BRO! (my bad for da caps)

Explanation:

Evidence-based practice (EBP) is the idea that occupational practices ought to be based on scientific evidence. That at first sight may seem to be obviously desirable, but the proposal has been controversial.

Happy to Help From, Adam

attashe74 [19]3 years ago

8 0

Bc U know what ur doing...?

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The mass of a regulation tennis ball is 57 g. The ball is in contact with the tennis racket for 30 ms. The ball was served at 73

yaroslaw [1]

Answer:

Correct answer: F₂ = 104.5 N

Explanation:

Given:

m = 57 g = 57 · 10⁻³ kg

Δt = 30 ms = 30 · 10 ⁻³ seconds

V₁ = 73.14 m/s service speed

V₂ = 55 m/s returned speed

M = m · V Momentum or Impulse

You forgot to indicate what time the ball contact when returning.

We will assume that the time is the same Δt = 30 ms = 30 10 ⁻³ seconds.

The formula for calculating force is according to Newton's second law is:

F = ΔM / Δt = m · ΔV / Δt

Force during service is:

F₁ = 57 · 10⁻³ · 73.14 / 30 · 10 ⁻³ = 138.97 N

F₁ = 138.97 N

Returned force:

F₂ = 57 · 10⁻³ · 55 / 30 · 10 ⁻³ = 104.5 N

F₂ = 104.5 N

God is with you!!!

8 0

3 years ago

I need a walk through please

babymother [125]

Answer:

11,100 N

Explanation:

Draw the car on the incline. Label the weight and normal forces. Call the direction normal to the incline y, and the direction parallel to the incline x.

If it helps, rotate the incline so that the surface of the incline is flat.

Use trigonometry to determine the components of the weight force. The y component of the weight is:

Wᵧ = mg cos θ

Wᵧ = (1150 kg) (9.8 m/s²) (cos 8.70°)

Wᵧ = 11,100 N

7 0

1 year ago

In a Rutherford scattering experiment a target nucleus has a diameter of 1.34×10-14 m. The incoming α particle has a mass of 6.6

Rasek [7]

Answer:

E = 2.5 x 10⁻¹⁴ J

Explanation:

given,

diameter = 1.33 x 10⁻¹⁴ m

mass = 6.64 x 10⁻²⁷ kg

wavelength is equal to diameter

de broglie wavelength equal to diameter

$\lambda = \dfrac{h}{mv}$

$1.33 \times 10^{-14}= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times v}$

$v= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times 1.33 \times 10^{-14}}$

v = 7.5 x 10⁶ m/s

Kinetic energy is equal to

$E = \dfrac{1}{2}mv^2$

$E = \dfrac{1}{2}\times 6.64 \times 10^{-27}\times (7.5\times 10^6)^2$

E = 2.5 x 10⁻¹⁴ J

8 0

2 years ago

The mass of an object is 275.32g and its density is 7.562g/cm 3 . Calculate its volume by keeping significant figures in view.

Genrish500 [490]

Answer:

36.408cm3

Explanation:

Since we acknowledge that density is d= m/v, once we switch it up to maintain v as the number to be found it will change to v=m/d. Therefore, 275.32/7.562 is 36.408 and the unit is cm cube!

Hope that helped!!

8 0

3 years ago

A Carnot engine operates between reservoirs at 600 and 300 K. If the engine absorbs 100 J per cycle at the hot reservoir, what i

PIT_PIT [208]

Answer:

W =50 J

Explanation:

given data:

T_h=600 k

T_L=300 k

Q_h=100 J

required:

<u>solution:</u>

║W║=║Q_h║(1-T_L/T_h)

=50 J

7 0

2 years ago

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