Answer:
I am not sure but I think the correct answer is c
I'm assuming that the 1/3 is an exponent.
If so, then
![2^{1/3} = \sqrt[3]{2}](https://tex.z-dn.net/?f=2%5E%7B1%2F3%7D%20%3D%20%5Csqrt%5B3%5D%7B2%7D)
Which is the cube root of 2. Raising any value to the 1/3 power is the same as taking the cube root.
Answer:
Bsjwkwkwkkenenrnrnrbtbbtbfbfnrntnt rnrnrkkrjrjr
Step-by-step explanation:
bdbrbrbr
9514 1404 393
Answer:
see attached
Step-by-step explanation:
Top down, left to right, the sums are ...
1/3 +3/6 = 2/6 +3/6 = 5/6 . . . pink
1 1/5 + 1 2/10 = 1 1/5 + 1 1/5 = (1 +1) +(1/5 +1/5) = 2 2/5 . . . green
2 2/6 +1 2/8 = 2 1/3 +1 1/4 = (2 +1) +(4/12 +3/12) = 3 7/12 . . . violet
1/7 +2/3 = 3/21 +14/21 = 17/21 . . . yellow
2 3/4 +2/6 = 2 9/12 +4/12 = 2 13/12 = 3 1/12 . . . brown
Answer:
<u>There are 17 terms in the sequence</u>
Step-by-step explanation:
<u>Arithmetic Sequence
</u>
An arithmetic sequence is a list of numbers with a definite pattern by which each term is calculated by adding or subtracting a constant number called common difference to the previous term. If n is the number of the term, then:

Where an is the nth term, a1 is the first term, and r is the common difference.
In the problem at hand, we are given the first term a1=13, the last term an=-23, and the common difference r=-2 1/4. Let's solve the equation for n:

We need to express r as an improper or proper fraction:

Substituting:



n=17
There are 17 terms in the sequence