Answer:
The heat capacity of the calorimeter is 4.76 kJ/°C
Explanation:
Step 1: Data given
1.00 mol of glucose releases 2820 kJ of heat
Mass of glucose = 2.0 grams
Mass of water = 1000 grams
The temperature increases with 3.5 °C
Step 2: Calculate moles
moles glucose = mass glucose / molar mass glucose
moles glucose = 2.0 grams / 180.16 g/mol
moles glucose = 0.0111 moles
Step 3: Calculate heat produced by the combustion
Heat produced = 2820 kJ/mol * 0.0111 moles
Heat produced = 31.302 kJ = 31302 J
Step 4: Calculate heat absorbed by the water
Q = m*c*ΔT
⇒ with m = the mass of water = 1000 grams
⇒ with c = the specific heat of water = 4.184 J/g°C
⇒ with ΔT = The change in temperature = 3.5 °C
Q = 1000 * 4.184 *3.5
Q = 14644 J absorbed by the water
Step 5: Calculate heat basorbed by the calorimeter
Q = 31302 - 14644 = 16658 J absorbed by the calorimeter
Step 6: Calculate the heat capacity of the calorimeter
c= 16658 J / 3.5 °C
c = 4759 J/°C = 4.76 kJ/°C
The heat capacity of the calorimeter is 4.76 kJ/°C
