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The answer to your question is C
Answer:
Explanation:
i. From solid to liquid (melting)
For melting to occur, heat must be absorbed by the substance being melted. When the substance gains significant amount of heat, its particles begins to vibrate and move on top of one another.
ii. From liquid to solid (freezing or hardening)
In this phase change, heat is removed from the system. This allows for the molecules to lose their kinetic energies and form an ordered arrangement from their liquid or molten state.
iii. From liquid to gas (evaporation)
As randomness continues to increase, more heat is absorbed to break the attractive forces between molecules of liquids. Phase change from liquid to gas is a heat absorbing process.
iv. From gas to liquid (condensation)
In condensation, heat is lost by a substance. To condense or collect gas particles together, heat must be removed from the system. This allows for a diminished kinetic energy among the particles of the system.
Answer:
Cu(s) + 2Ag⁺(aq) → Cu²⁺(aq) + 2Ag(s).
Explanation:
- Since E°Ag⁺ is more positive (+ 0.80 V) than that of E°Cu²⁺ (+ 0.34 V).
So, Ag will be the cathode that the reduction reaction is occurred on it and Cu will be the anode where the oxidation reaction is occurred on it.
Cu(s) + 2Ag⁺(aq) → Cu²⁺(aq) + 2Ag(s).
- Ag⁺ is reduced to Ag and Cu is oxidized to Cu²⁺.