Answer:
7.12 mm
Explanation:
From coulomb's law,
F = kqq'/r².................... Equation 1
Where F = force, k = proportionality constant, q and q' = The two point charges, r = distance between the two charges.
Make r the subject of the equation,
r = √(kqq'/F).......................... Equation 2
Given: q = q' = 75.0 nC = 75×10⁻⁹ C, F = 1.00 N
Constant: k = 9.0×10⁹ Nm²/C².
Substitute into equation 2
r = √[ (75×10⁻⁹ )²9.0×10⁹/1]
r = 75×10⁻⁹.√(9.0×10⁹)
r = (75×10⁻⁹)(9.49×10⁴)
r = 711.75×10⁻⁵
r = 7.12×10⁻³ m
r = 7.12 mm
Hence the distance between the point charge = 7.12 mm
HEY THERE!!
For a given principal quantum number or n, the corresponding angular quantum number or l is equivalent to a range between 0 and (n-1) .
This means that the angular quantum number for a principal quantum number of 2 is equivalent to:
l = 0 -> (n-1) = 0 -> (2-1) = 0 -> 1
So the answer is 0, 1
HOPE IT HELPED YOU.
It B I just took the test ;)
