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Lera25 [3.4K]
3 years ago
6

In a pickup game of dorm shuffleboard,students crazed by final exams use a broom to propel a calculus book along the dorm hallwa

y. If the 3.5 kg book is pushed from rest through a distance of 0.90 m by the horizontal 25 N force from the broom and then has a speed of 1.60 m/s,what is the coefficient of kinetic friction between the book and floor?
Physics
1 answer:
Yakvenalex [24]3 years ago
6 0

Answer:

Coefficient of friction between the book and floor is 0.582.

Explanation:

Using the velocity formula;

v^2 = 2as

a = v^2/(2s)

a = 1.6^2/(2*0.9)

a = 2.56/1.8

a = 1.42 m/s^2

the force necessary to give the book the acceleration is  

F = ma = 3.5*1.42 (m is mass of the book i.e. 3.5 kg)

F = 4.98 N

The difference in the force is the friction force, which is

Ff = 25 - 4.98 = 20 N

Ff = mgμ

where μ is coefficient of friction and g is acceleration due to gravity that is 9.8 m/s^2

μ = Ff/mg

μ = 20/(3.5*9.81)

μ = 0.582

Coefficient of friction between the book and floor is 0.582.

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A 100 N force is applied to a 50 kg crate resting on a level floor. The coefficient of kinetic friction is 0.15. What is the acc
Nookie1986 [14]

The acceleration of the crate after it begins to move is 0.5 m/s²

We'll begin by calculating the the frictional force

Mass (m) = 50 Kg

Coefficient of kinetic friction (μ) = 0.15

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 50 × 10 = 500 N

<h3>Frictional force (Fբ) =?</h3>

Fբ = μN

Fբ = 0.15 × 500

<h3>Fբ = 75 N</h3>

  • Next, we shall determine the net force acting on the crate

Frictional force (Fբ) = 75 N

Force (F) = 100 N

<h3>Net force (Fₙ) =?</h3>

Fₙ = F – Fբ

Fₙ = 100 – 75

<h3>Fₙ = 25 N</h3>

  • Finally, we shall determine the acceleration of the crate

Mass (m) = 50 Kg

Net force (Fₙ) = 25 N

<h3>Acceleration (a) =?</h3>

a = Fₙ / m

a = 25 / 50

<h3>a = 0.5 m/s²</h3>

Therefore, the acceleration of the crate is 0.5 m/s²

Learn more on friction: brainly.com/question/364384

8 0
2 years ago
Lillle is running. She increases her initial speed of 30 km/h to 40 km/h so she
Alex777 [14]

Answer

200km {h}^{ - 2}

Explanation

Acceleration =  \frac{final \:  \:  \: velocity - initial \:  \: velocity }{time}  \\  =  \frac{(40 - 30)km {h}^{ - 1} }{0.05h}  \\  =  \frac{10}{0.05}  \\  = 200km {h}^{ - 2}

Hope this helps you.

Let me know if you have any other questions :-):-)

6 0
3 years ago
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A race car has a centriple acceleration of 15.625 m/s as it goes around a curve if the curve is a circle with radius 40 m what’s
Elanso [62]

Answer:

25 m/s

Explanation:

Centripetal acceleration is the square of the tangential velocity divided by the radius.

a = v² / r

15.625 m/s² = v² / (40 m)

v² = 625 m²/s²

v = 25 m/s

The speed of the car is 25 m/s.

7 0
3 years ago
What is helpful for motivating a person to achieve a fitness or health goal?
tresset_1 [31]

Answer:

I think it's b

Explanation:

seems about right

6 0
2 years ago
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Hey guys i need help (potential energy)
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Explanation:

Michael should put the vase at the bottom of the shelf to reduce the potential energy because the height of the vase to the floor is nearly zero.

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