2 years ago

Please help me...physis question

Physics

1 answer:

tamaranim1 [39]2 years ago

8 0

Uh- whatever the person before me said

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here we know that

$h = 18 m$

$g = 9.8 m/s^2$

now by the above formula

$18 = \frac{1}{2}*9.8* t^2$

$18 = 4.9 t^2$

$t = 1.92 s$

now in the same time interval we can say the distance moved by it will be

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$d = 8.2 * 1.92 = 15.7 m$

so it will fall at a distance 15.7 m from its initial position

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