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Step2247 [10]
3 years ago
15

Please help me...physis question

Physics
1 answer:
tamaranim1 [39]3 years ago
8 0
Uh- whatever the person before me said
You might be interested in
What happens to energy and matter when a wave moves through space?
vivado [14]

Answer:

energy can move from one location to another, the particles of matter in the medium return to their fixed position. A wave transports its energy without transporting matter.

4 0
3 years ago
What's the average speed of an object moving 3790 meters in 249 s.
NISA [10]

Heya!!

For calculate velocity, lets applicate formula

                                                 \boxed{d = v * t}

                                               <u>Δ   Being   Δ</u>

                                         d = Distance = 3790 m

                                             t = Time = 249 s

                                             v = Velocity = ?

⇒ Let's replace according the formula and clear "v":

\boxed{v= 3790\ m / 249\ s}

⇒ Resolving

\boxed{ v = 15,22 \ m/s }

Result:

The velocity is <u>15,22 meters per second.</u>

Good Luck!!

4 0
3 years ago
A student on an amusement park ride moves in circular path with a radius of 3.5 m once every 4.5 s. What is the tangential veloc
nata0808 [166]

Answer:

the tangential velocity of the student is 4.89 m/s.

Explanation:

Given;

the radius of the circular path, r = 3.5 m

duration of the motion, t = 4.5 s

let the student's tangential velocity = v

The tangential velocity of the student is calculated as follows;

v = \frac{2\pi r}{t} \\\\v = \frac{2 \pi \times 3.5}{4.5} \\\\v = 4.89 \ m/s

Therefore, the tangential velocity of the student is 4.89 m/s.

6 0
3 years ago
A storm is moving at 15 km/hr what to do to determine its velocity
WINSTONCH [101]
Check the current weather map for 2 different times, and see where the center of the storm is. That tells you what direction it's moving. With its speed and direction, you have its velocity.
6 0
4 years ago
Par 1/2
BaLLatris [955]

part 1

mass = ρ x V

mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg

PE (potential energy)= mgh

PE = 6608.2 kg x 9.81 x 403

PE = 2.61 x 10⁷ J

part 2

megaton of TNT (Mt) =4.2 x 10¹⁵ J

convert PE to Mt:

2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt

4 0
3 years ago
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