The. 3rd one the ram of the bus
Answer:8.8983N
Explanation:
Horizontal component=9xcos19
Horizontal component=9x0.9887
Horizontal component=8.8983N
Answer:
It's 1.0000042 times longer in summer than in winter. It represents a 1.6 centimeters difference between seasons.
Explanation:
The linear coefficient of thermal expansion for steel is about 
. From the equation of linear thermal expansion, we have:
Taking the winter day as the initial, and the summer day as the final, we can take the relationship between them:
![L_{summer}=L_{winter}[1+(1.2*10^{-7}\°C^{-1})(30\°C+5\°C)]\\\\L_{summer}=(1.0000042)L_{winter}](https://tex.z-dn.net/?f=L_%7Bsummer%7D%3DL_%7Bwinter%7D%5B1%2B%281.2%2A10%5E%7B-7%7D%5C%C2%B0C%5E%7B-1%7D%29%2830%5C%C2%B0C%2B5%5C%C2%B0C%29%5D%5C%5C%5C%5CL_%7Bsummer%7D%3D%281.0000042%29L_%7Bwinter%7D)
It means that the bridge is 1.0000042 times longer in summer than in winter. If we multiply it by the length of the bridge, we obtain that the difference is of about 1.6 centimeters between the two seasons.
Answer:
1.805 mm
Explanation:
Extension in the steel wire = WL_{steel}/AE_{steel}
Extension in the aluminium wire = WL_{Al}/AE_{Al}
Total extension = W/A * (L_{steel}/E_{steel} + L_{Al}/E_{Al})
we have:
W = mg
W = 5 × 9.8
W = 49 N
Area A = π/4 × (0.001)²
= 7.85398 × 10 ⁻⁷ m²
Total extension = W/A * (L_{steel}/E_{steel} + L_{Al}/E_{Al})
Total extension = 49/ 7.85398 × 10 ⁻⁷ ( (1.5/ 200×10⁹) + 1.5/ 70×10⁹))
Total extension = 0.0018048
Total extension = 1.805 mm
Thus, the total extension = the resulting change in the length of this composite wire = 1.805 mm
We have: Q = m.s.Δt
m = Q / s.Δt
Here, Q = 19.4 J
s = 6.28 J/g C
Δt = 22.9
Substitute their values into the expression:
m = 19.4 / 6.28×22.9
m = 19.4 / 143.81
m = 0.135 g
In short, Your Answer would be Option A
Hope this helps!
