A force of 9.00 newtons acts at an angle of 19.0° to the horizontal. What is its component in the horizontal direction?
1 answer:
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Answer:
1.53 g
Explanation:
Given,
Initial speed = 30 m/s
Final speed = 0 m/s
Period of stretch, t = 2 s
average deceleration = ?
we know
a = -15 m/s²
Deceleration of the jumper = 15 m/s²
Deceleration in terms of g
Hence, the deceleration of the jumper is equal to 1.53 g
Answer:
The final velocity is 28.14 m/s
Yes the angle of projection matters
Explanation:
Given;
initial velocity of the water balloon, u = 20 m/s
height of the building, h = 20 m
let the final speed of the ball when it hits the ground = v
The final speed is calculated as follows;
v² = u² + 2gh
v² = (20)² + 2(9.8)(20)
v² = 400 + 392
v² = 792
v = √792
v = 28.14 m/s
Yes the angle matters, if the balloon had been dropped at a certain angle, the final velocity would have been estimated using the following formula;
where;
θ is the angle of projection, which accounts for the vertical component of the velocity.