If a 5000-kg is moving at a speed of 43 m/s, what is its momentum?
1 answer:
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Answer:
Explanation:
If we have a periodic wave we need to satisfy the following basic relationship:
From the last formula we see that the velocity is proportional fo the frequency.
For this case we have the following info given by the problem:
We know that the frequency is the reciprocal of the period so we have this formula:
And if we replace we got:
Now since we have the value for the wavelength we can find the velocity like this:
And if we convert this into cm/s we got:
Answer:
Explanation:
a ) angular frequency ω =
k is spring constant and m is mass attached
ω =
= 3.6515 rad / s
frequency of oscillation n = 3.6515 / (2 x 3.14)
= .5814 s⁻¹
x = .1 mcos(ωt)
= .1 mcos(3.6515t)
b ) maximum speed = ωA , A is amplitude
= 3.6515 x .1
= .36515 m /s
36.515 cm /s
maximum acceleration = ω²A
= 3.6515² x .1
= 1.333 m / s²
c ) Kinetic energy at displacement x
= 1/2 m ω²( A²-x²)
potential energy =1/2 m ω²x²
so 1/2 m ω²( A²-x²) = 1/2 m ω²x²
A²-x² = x²
2x² = A²
x = A / √2