All categories

2 years ago

If a 5000-kg is moving at a speed of 43 m/s, what is its momentum?

Physics

1 answer:

Eduardwww [97]2 years ago

4 0

Answer:

215000kgm/s

Explanation:

Given parameters:

Mass of the moving body = 5000kg

Velocity = 43m/s

Unknown:

Momentum = ?

Solution:

The momentum of a body is the amount of motion a body possess.

It is mathematically expressed as:

Momentum = mass x velocity

Now:

Momentum = 5000 x 43 = 215000kgm/s

You might be interested in

Question 24 1 pts Find the voltage in an extension cord having a 0.0600 22 resistance and through which a 5.00A current is flowi

Neporo4naja [7]

The voltage in the extension cord is 30 V.

The problem above can be solved using ohm's law

⇒ Formula:

V = IR.................. Equation 1

⇒ Where:

V = Voltage in the extension cord

I = Current flowing through the extension cord
R = Resistance of the extension cord.

From the question, I think there was a slight error in the value of the current given it suppose to be 500 A, and not 5.00 A

⇒ Given:

I = 500 A
R = 0.06 ohms

⇒ Substitute these values into equation 1

V = 500(0.06)
V = 30 V

Hence the voltage in the extension cord is 30 V

Learn more about voltage here: brainly.com/question/4429782

6 0

2 years ago

A machine part has the shape of a solid uniform sphere of mass 250 g and a diameter of 4.30 cm. It is spinning about a frictionl

zysi [14]

Answer: $\alpha =9.302\ rad/s^2$

Explanation:

Given

mass of sphere $m=250\ gm$

diameter of sphere $d=4.30\ cm$

radius $r=\frac{4.30}{2}\ cm$

$f=0.0200\ N$

friction will provide resisting torque so

$f\times r=I\times \alpha$

where $I=\text{moment of Inertia}$

$f=\text{friction force}$

$\alpha =\text{angular acceleration}$

$I=\frac{2}{5}mr^2$

$0.02\times r=\frac{2}{5}mr^2\times \alpha$

$\alpha =\frac{5}{2r}\times f$

$\alpha =\frac{5}{2}\times \frac{2}{4.3\times 10^{-2}}\times 0.02$

$\alpha =9.302\ rad/s^2$

(b)time taken to decrease its rotational speed by $21\ rad/s$

$t=\dfrac{\Delta \omega }{\alpha }$

$t=\dfrac{21}{9.302}$

$t=2.25\ s$

6 0

2 years ago

Your oven has a power rating of 5000 watts. How many kilowatts is this ?

Gekata [30.6K]

1,000 watts = 1 kilowatt
2,000 watts = 2 kilowatts
3,000 watts = 3 kilowatts
4,000 watts = 4 kilowatts
<em>5,000 watts = 5 kilowatts</em>

8 0

2 years ago

Describe the phenomenon of lightning?

masha68 [24]

Lightning is a naturally occurring electrostatic discharge during which two electrically charged regions in the atmosphere or ground temporarily equalize themselves, causing the instantaneous release of as much as one gigajoule of energy.

3 0

2 years ago

A force of 120 N is applied to the front of a sled so as to pull the sled a distance of 165

Marrrta [24]

Answer:

<h3>The answer is 19,800 J</h3>

Explanation:

The work done by an object can be found by using the formula

<h3>workdone = force × distance</h3>

From the question

force = 120 N

distance = 165 m

We have

work done = 120 × 165

We have the final answer as

Hope this helps you

8 0

3 years ago