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forsale [732]
3 years ago
11

Why are the Inner Planets composed mostly of rock and the Outer Planets composed mostly of gas

Physics
1 answer:
Sonja [21]3 years ago
5 0
The temperature of of solar system and how far away they are from the sun.
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As an acapulco cliff diver drops to the water from a height of 42.0 m, his gravitational potential energy decreases by 27,500 j.
seraphim [82]

We know that potential energy is simply energy due to position which has the formula:

PE = mass * gravity * height

We know that mass * gravity is weight, therefore:

PE = weight * height

27500 J = weight * 42 m

<span>weight = 654.76 Newtons</span>

3 0
3 years ago
A 2000 kg car moves along a horizontal road at speed vo
cluponka [151]

Answer:

The shortest possible stopping distance of the car is 175.319 meters.

Explanation:

In this case we see that driver use the brakes to stop the car by means of kinetic friction force. Deceleration of the car is directly proportional to kinetic friction coefficient and can be determined by Second Newton's Law:

\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a (Eq. 1)

\Sigma F_{y} = N-m\cdot g = 0 (Eq. 2)

After quick handling, we get that deceleration experimented by the car is equal to:

a = -\mu_{k}\cdot g (Eq. 3)

Where:

a - Deceleration of the car, measured in meters per square second.

\mu_{k} - Kinetic coefficient of friction, dimensionless.

g - Gravitational acceleration, measured in meters per square second.

If we know that \mu_{k} = 0.0735 and g = 9.807\,\frac{m}{s^{2}}, then deceleration of the car is:

a = -(0.0735)\cdot (9.807\,\frac{m}{s^{2}} )

a = -0.721\,\frac{m}{s^{2}}

The stopping distance of the car (\Delta s), measured in meters, is determined from the following kinematic expression:

\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a} (Eq. 4)

Where:

v_{o} - Initial speed of the car, measured in meters per second.

v - Final speed of the car, measured in meters per second.

If we know that v_{o} = 15.9\,\frac{m}{s}, v = 0\,\frac{m}{s} and a = -0.721\,\frac{m}{s^{2}}, stopping distance of the car is:

\Delta s = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(15.9\,\frac{m}{s} \right)^{2}}{2\cdot \left(-0.721\,\frac{m}{s^{2}} \right)}

\Delta s = 175.319\,m

The shortest possible stopping distance of the car is 175.319 meters.

8 0
3 years ago
How would a graph of velocity vs. Time would look like, if there was no motion at all? (Draw your graph)
Y_Kistochka [10]

Answer:

no motion means no velocity, so the y values willl always be 0 as ur time (x) value increses

Explanation:

7 0
2 years ago
If an atom has 7 valence electrons, how many electrons does it need to gain to achieve a stable electron configuration?
Doss [256]
It only needs one more to make it stable 
6 0
2 years ago
Read 2 more answers
In three to five sentences, identify the acid, base, conjugate acid, and conjugate base. Use patterns in the periodic table to e
Oliga [24]

A conjugate acid is formed from the base  by accepting a proton from the acid .

A conjugate base is obtained from the Brownstead - Lowry acid when it looses a proton while the conjugate acid is obtained from the Brownstead - Lowry base when it accepts a proton. In the Brownstead - Lowry sense, acid base reaction involves the loss or gain of a proton.

Consider the hypothetical reaction; AH + :B ⇄ BH + :A. The specie BH is the conjugate acid while the specie  :B is the  Brownstead - Lowry base . The specie :A is the conjugate base while the specie AH is the  Brownstead - Lowry acid.

Learn more about conjugate acid: brainly.com/question/10468518

6 0
2 years ago
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