If the cd rotates clockwise at 500 rpm (revolutions per minute) while the last song is playing, and then spins down to zero angu

Question

4 years ago

14

If the cd rotates clockwise at 500 rpm (revolutions per minute) while the last song is playing, and then spins down to zero angu

lar speed in 2.60 s with constant angular acceleration, what is α, the magnitude of the angular acceleration of the cd, as it spins to a stop? express your answer in radians per second squared

Physics

1 answer:

Katen [24] · Answer 1 · 2021-12-04T11:41:00+03:00

Katen [24]4 years ago

3 0

The solution for this problem is:

500 revolution per minute = 8.33rev /s = 2π*8.33 rad /s = 52.36 rad /s

Angular velocity ω = 2π N

Angular acceleration α= (ω2 - ω1) /t

ω2 = 0

α = - ω1/t = -2π N /t

N = 500 rpm = 8.33 r p s.

α = -2π 8.33 /2.6 =- 20 rad/s^2