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Hatshy [7]
3 years ago
15

Investigating arson can be a very complicated and complex job, as you learned in the unit! It is also generally a time sensitive

matter. Forensic scientists who investigate arson must not only act quickly, but also methodically.
In order to practice how you would respond during an arson investigation, you will be creating a ‘game plan’ or ‘fire investigation timeline’ for what you would do upon arriving at the scene of a fire. Using what you learned in the unit as well as any necessary online research, you will articulate each step that would take place during your investigation. Be sure to number your steps and keep in mind any unexpected situations that might occur.

For example: “First, I would want to find the fire’s origin and look for signs of accelerant use. If I was able to locate the origin, I would do my best to preserve the area. If not, …”

Your ‘timeline’ should be detailed but it does not need to be as extensive as a research paper or essay. You can format your timeline however you like – as an actual timeline, a bulleted list, or short paragraphs as long as you include a clear format like first, second, third, etc. Be sure to include at least six steps.

You can create your ‘timeline’ in a word processing program or a slide presentation. You will be graded on the accuracy of your timeline as well as mechanics and grammar. For more details, see the rubric below.

The Plot Explodes (ongoing activity)
An explosion has occurred in a house down the street from Dr. Fisher’s apartment! Fortunately, the fire was controlled before it could spread to the rest of the block. No one was in the house when the blast occurred. All personal possessions in the house, including a computer and several filing cabinets, have been destroyed.

Property records show that Dr. Fisher’s former patient, Bill, bought the house a year ago. He was still Dr. Fisher’s patient at that time. Apparently, their relationship was strained. Bill had tried to sue Dr. Fisher for malpractice, without success.

When investigators searched the scene, they found bomb fragments with homemade electronics. They traced the electronics to a nearby store where Bill is a customer. They also found a metal cabinet at the scene that survived the blast. Inside the cabinet were several boxes of .38 caliber brass bullets.

So far, investigators have been unable to locate Bill for questioning.

Who do you think bombed Bill’s house, and why? (one to two sentences)
What other types of explosion or fire evidence might you look for within the blast radius? (two to three sentences)
Does this incident change your theory on Dr. Fisher’s murder? Explain. (three to five sentences)
Physics
1 answer:
Andrews [41]3 years ago
7 0

Answer:

First, I would want to find what started the fire and why that's what caused it.

Second, I would take pictures of the area where the fire started if found.

Third, I would interview the witnesses.

Fourth, I would document the scene and write down everything that I see and what the people seen/heard happen.

Fifth, They need to do a full scene investigation.

Sixth, They need to do a follow up investigation.  

Who do you think bombed Bill’s house, and why? (one to two sentences) I think Bill bombed his own house because he did not want to be caught. He most likely bombed his house with all his belongings so that he couldn't be traced.

What other types of explosion or fire evidence might you look for within the blast radius? (two to three sentences) Within the blast radius I would search for chemical residue. I would try to find Bill as soon as possible to match the chemical residue on his clothes if there is any.

Does this incident change your theory on Dr. Fisher’s murder? Explain. (three to five sentences) As sad as it is I believe that Dr. Fisher was murdered by his own patient Bill since they had a very hostile relationship. The incident of Bill’s house bombing doesn’t change my theory on Dr. Fisher’s murder, in fact, it further consolidates my theory of Bill being the murderer since Bill wanted to get rid of the evidence so that’s why he bombed his own house.

Explanation:

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An isolated conducting sphere has a 17 cm radius. One wire carries a current of 1.0000020 A into it. Another wire carries a curr
notsponge [240]

14 ms is required to reach the potential of 1500 V.

<u>Explanation:</u>

The current is measured as the amount of charge traveling per unit time. So the charge of electrons required for each current is determined as the product of current with time.

       Charge = Current \times Time

As two different current is passing at two different times, the net charge will be the different in current.  So,

        \text { Charge }=(1.0000020-1.0000000) \times t=2 \times 10^{-6} \times t

The electric voltage on the surface of cylinder can be obtained as the ratio of charge to the radius of the cylinder.

        V=\frac{k q}{R}

Here k = 9 * 10^9, q is the charge and R is the radius. As q=2 \times 10^{-6} \times t and R =17 cm = 0.17 m, then the voltage will be

        V=\frac{9 \times 10^{9} \times 2 \times 10^{-6} \times t}{0.17}

The time is required to find to reach the voltage of 1500 V, so

1500 =\frac{9 \times 10^{9} \times 2 \times 10^{-6} \times t}{0.17}

\begin{aligned}&t=\frac{1500 \times 0.17}{\left(9 \times 10^{9} \times 2 \times 10^{-6}\right)}\\&t=14.1666 \times 10^{-3} s=14\ \mathrm{ms}\end{aligned}

So, 14 ms is required to reach the potential of 1500 V.

3 0
3 years ago
What factor affects weight( what force causes weight to change)
Alex Ar [27]

Answer:

Gravitational force affects weight, weight changes with change in gravity

Hope it helped u,

mark as the brainliest

^_^

3 0
3 years ago
A car starts from rest and accelerates at a constant rate after the car has gone 50 m it has a speed of 21 m/s what is the accel
Leya [2.2K]

Answer:

4.41 m/s^2

Explanation:

(v_f)^2 - (v_i)^2 = 2a * change in distance

(21)^2 - (0)^2 = 2a * 50

a = (21^2)/(2*50)

a = 4.41 m/s^2

3 0
3 years ago
Un the way to the moon, the Apollo astro-
kherson [118]

Answer:

Distance =  345719139.4[m]; acceleration = 3.33*10^{19} [m/s^2]

Explanation:

We can solve this problem by using Newton's universal gravitation law.

In the attached image we can find a schematic of the locations of the Earth and the moon and that the sum of the distances re plus rm will be equal to the distance given as initial data in the problem rt = 3.84 × 108 m

r_{e} = distance earth to the astronaut [m].\\r_{m} = distance moon to the astronaut [m]\\r_{t} = total distance = 3.84*10^8[m]

Now the key to solving this problem is to establish a point of equalisation of both forces, i.e. the point where the Earth pulls the astronaut with the same force as the moon pulls the astronaut.

Mathematically this equals:

F_{e} = F_{m}\\F_{e} =G*\frac{m_{e} *m_{a}}{r_{e}^{2}  } \\

F_{m} =G*\frac{m_{m}*m_{a}  }{r_{m} ^{2} } \\where:\\G = gravity constant = 6.67*10^{-11}[\frac{N*m^{2} }{kg^{2} } ] \\m_{e}= earth's mass = 5.98*10^{24}[kg]\\ m_{a}= astronaut mass = 100[kg]\\m_{m}= moon's mass = 7.36*10^{22}[kg]

When we match these equations the masses cancel out as the universal gravitational constant

G*\frac{m_{e} *m_{a} }{r_{e}^{2}  } = G*\frac{m_{m} *m_{a} }{r_{m}^{2}  }\\\frac{m_{e} }{r_{e}^{2}  } = \frac{m_{m} }{r_{m}^{2}  }

To solve this equation we have to replace the first equation of related with the distances.

\frac{m_{e} }{r_{e}^{2}  } = \frac{m_{m} }{r_{m}^{2} } \\\frac{5.98*10^{24} }{(3.84*10^{8}-r_{m}  )^{2}  } = \frac{7.36*10^{22}  }{r_{m}^{2} }\\81.25*r_{m}^{2}=r_{m}^{2}-768*10^{6}* r_{m}+1.47*10^{17}  \\80.25*r_{m}^{2}+768*10^{6}* r_{m}-1.47*10^{17} =0

Now, we have a second-degree equation, the only way to solve it is by using the formula of the quadratic equation.

r_{m1,2}=\frac{-b+- \sqrt{b^{2}-4*a*c }  }{2*a}\\  where:\\a=80.25\\b=768*10^{6} \\c = -1.47*10^{17} \\replacing:\\r_{m1,2}=\frac{-768*10^{6}+- \sqrt{(768*10^{6})^{2}-4*80.25*(-1.47*10^{17}) }  }{2*80.25}\\\\r_{m1}= 38280860.6[m] \\r_{m2}=-2.97*10^{17} [m]

We work with positive value

rm = 38280860.6[m] = 38280.86[km]

<u>Second part</u>

<u />

The distance between the Earth and this point is calculated as follows:

re = 3.84 108 - 38280860.6 = 345719139.4[m]

Now the acceleration can be found as follows:

a = G*\frac{m_{e} }{r_{e} ^{2} } \\a = 6.67*10^{11} *\frac{5.98*10^{24} }{(345.72*10^{6})^{2}  } \\a=3.33*10^{19} [m/s^2]

6 0
3 years ago
Please please please please help
aivan3 [116]

Answer:

I am pretty sure its the second one but I could be wrong sorry if I am.

Explanation:

:D

4 0
3 years ago
Read 2 more answers
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