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Readme [11.4K]
3 years ago
7

You drop a 0.375 kg ball from a height of 1.37 m. It hits the ground and bounces up again to a height of 0.67 m. How much energy

did it lose in the bounce?
Physics
1 answer:
Radda [10]3 years ago
6 0

2.57 joule energy lose in the bounce .

<u>Explanation</u>:

when ball is the height of 1.37 m from the ground  it has some gravitational potential energy with respect to hits the ground  

Formula for gravitational potential energy given by  

Potential Energy = mgh

Where ,

m = mass  

g = acceleration due to gravity  

h = height

Potential energy when ball hits the ground

m= 0.375 kg

h = 1.37 m

g = 9.8 m/s²

Potential Energy = 0.375\times9.8\times1.37

Potential Energy = 5.03 joule

Potential energy when ball bounces up again

h= 0.67 m

Potential Energy = 0.375\times0.67\times9.8

Potential Energy = 2.46 joule

Energy loss = 5.03 - 2.46 = 2.57 joule

2.57 joule energy lose in the bounce

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Answer:

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Explanation:

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#3. Tectonic plates are composed of oceanic lithosphere and thicker continental lithosphere, each topped by its own kind of crust. The two types of tectonic plates are continental and oceanic tectonic plates.

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Hope this helps!

Have a nice day!

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<em>Pls consider marking my answer as </em><em>Brainliest</em><em>! It would mean a lot!</em>

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Answer:

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a = 7.8 m/s^2

Explanation:

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m = mass of the skydiver

a = acceleration caused by Fnet

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f(air) = frictional force due to air resistance

Fnet = W - f(air)

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Answer:

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Explanation:

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Answer:

8 time increase in K.E.

Explanation:

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