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Wewaii [24]
3 years ago
7

What is the term for collecting information about the physical world via the senses or a scientific instrument?

Physics
2 answers:
Alex777 [14]3 years ago
6 0
The answer is A

an  experiment is a scientific way of gathering data about the world around us using the scientific method and the proper tools to do so

a phenomenon is something that happens that we may not necessarily explain

a theory is something that we use to explain the world around us that we can't prove 100% but is accepted as the truth in most cases until proven otherwise

and an observation can imply you are just watching something happen and no scientific studies or uses apply

Ulleksa [173]3 years ago
4 0

Answer:D

Explanation:

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the force acting perpendicularly on unit area of surface

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Assume that the home construction industry is perfectly competitive and in long-run competitive equilibrium. It follows that: A.
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B. Marginal cost equals long-run average total cost.

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What happens in the process of gravitational condensation?
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The specific heat of substance A is greater than that of substance B. Both A and B are at the same initial temperature when equa
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Answer:

m_A c_{pA} (T_{fA} -T) = m_B c_{pB} (T_{fB}- T)

For this case, if we try to find the final temperature of A and B, we see that we will obtain an expression in terms of specific heats and masses, from the information given we know the relationship between specific heats, but we don't know the relationship that exists among the masses, then the best option for this case is:

d) More information is needed

(The relation between the masses is not given)

Explanation:

For this case we know the following info:

c_{pA} > c_{pB}

Where c means specific heat for the substance A and B.

We also know that the initial temperatures for both sustances are equal:

T_{iA}= T_{iB}

We assume that we don't have melting or vaporization in the 2 substances. So we just have presence of sensible heat given by this formula:

Q = m c_p \Delta T

And for this case we know that Both A and B are at the same initial temperature when equal amounts of energy are added to them, so then we have this:

Q_A = Q_B

And if we replace the formula for sensible heat we got:

m_A c_{pA} \Delta T_A = m_B c_{pB} \Delta T_B

And if we replace for the change of the temperature we got:

m_A c_{pA} (T_{fA} -T_{iA}) = m_B c_{pB} (T_{fB}- T_{iB})

And since T_{iA}= T_{iB}= T we have this:

m_A c_{pA} (T_{fA} -T) = m_B c_{pB} (T_{fB}- T)

For this case, if we try to find the final temperature of A and B, we see that we will obtain an expression in terms of specific heats and masses, from the information given we know the relationship between specific heats, but we don't know the relationship that exists among the masses, then the best option for this case is:

d) More information is needed

(The relation between the masses is not given)

4 0
3 years ago
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