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bagirrra123 [75]
3 years ago
10

What is frequency of light is emitted when an electron jumps into the smallest orbit of hydrogen, coming from a very large radiu

s (assume infinity)?
Physics
1 answer:
mrs_skeptik [129]3 years ago
7 0

Answer:

3.28403\times 10^{15}\ Hz

Explanation:

n_1 = 1

n_2=\infty

h = Planck's constant = 6.626\times 10^{-34}\ m^2kg/s

The energy is given by

E(n)=E_1(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2})\\\Rightarrow E(1)=13.6\ eV

Energy is also given by

E=hf\\\Rightarrow f=\dfrac{E}{h}\\\Rightarrow f=\dfrac{13.6\times 1.6\times 10^{-19}}{6.626\times 10^{-34}}\\\Rightarrow f=3.28403\times 10^{15}\ Hz

The frequency of light emitted would be 3.28403\times 10^{15}\ Hz

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A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel d
Dmitry [639]

Answer:

the distance in meters traveled by a point outside the rim is 157.1 m

Explanation:

Given;

radius of the disk, r = 50 cm = 0.5 m

angular speed of the disk, ω = 100 rpm

time of motion, t = 30 s

The distance in meters traveled by a point outside the rim is calculated as follows;

\theta = \omega t\\\\\theta = (100 \frac{rev}{\min}  \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 s} ) \times (30 s)\\\\\theta = 100 \pi \ rad\\\\d = \theta r\\\\d = 100\pi  \ \times \ 0.5m\\\\d = 50 \pi \ m = 157.1 \ m

Therefore, the distance in meters traveled by a point outside the rim is 157.1 m

6 0
3 years ago
A dog is 60m away while moving at constant velocity of 10m/s towards you. Where is the dog after 4 seconds?
evablogger [386]
20m away

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4 0
3 years ago
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If the result of your calculation of a quantity has si units kg•m^2/s^2•C, that quantity could be
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Workdone = Force * distance
Force = mass * acceleration
          = kg      *  ms⁻²
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Distance = m

So, Force * distance
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Apply laws of indices that says
x² * x³ = x²⁺³ = x⁵

Therefore, It would be kgm²s⁻²
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What are parts of<br> chromosomes.<br> Momcomes are made of
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Answer: dna

Explanation:

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