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svetoff [14.1K]
3 years ago
9

Which of the following pairs of terms directly relates to the actual brightness of a star?

Physics
2 answers:
Aloiza [94]3 years ago
7 0

Answer:

D. absolute magnitude and apparent magnitude

yan [13]3 years ago
5 0
D. Absolute magnitude and apparent magnitude
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ASAP ANSWER PLEASE WILL MARK BRAINLIEST
lisov135 [29]

Yes

Explanation:

It is a reasonable result obtained.

Error = true value - measured value

true value = 24.5

measured value = 24.2

Error =  24.5 - 24.2 = 0.3g

 The error reported in the reading is 0.3g

The reason why we had a disparity in the figures obtained from this measurement is primarily due to some erroneous scale.

The mixture at the end of the day is a solution.

We are expected to have the same mass but due to experimental or some form of random error introduced, we noticed a difference.

The value obtained is quite logical as we only had a deviation of 0.3g.

learn more:

Error brainly.com/question/2764830

#learnwithBrainly

6 0
3 years ago
A particular car engine operates between temperatures of 440°C (inside the cylinders of the engine) and 20°C (the temperature of
Step2247 [10]

One of the concepts to be used to solve this problem is that of thermal efficiency, that is, that coefficient or dimensionless ratio calculated as the ratio of the energy produced and the energy supplied to the machine.

From the temperature the value is given as

\eta = 1-\frac{T_L}{T_H}

Where,

T_L = Cold focus temperature

T_H = Hot spot temperature

Our values are given as,

T_L = 20\° C = (20+273) K = 293 K

T_H = 440\° C = (440+273) K = 713 K

Replacing we have,

\eta = 1-\frac{T_L}{T_H}

\eta = 1-\frac{293}{713}

\eta = 0.589

Therefore the maximum possible efficiency the car can have is 58.9%

4 0
3 years ago
The Hall effect can be used to calculate the charge-carrier number density in a conductor. A conductor carrying current of 2.0 A
marysya [2.9K]

Answer:

option D

Explanation:

given,

A conductor is carrying current = 2.0 A is 0.5 mm thick

Hall voltage = 4.5 x 10-6 V

uniform magnetic field  =  1.2 T

density of the charge = n =?

hall voltage =V_h =\dfrac{i\ B}{n\ e\ L}

n = \dfrac{i\ B}{V\ e\ L}

n = \dfrac{2 \times 1.2 }{4.5 \times 10^{-6}\times 1.6 \times 10^{-19} \times 0.5 \times 10^{-3}}

n = 6.67 × 10²⁷ charges/m

hence the correct answer is option D

7 0
3 years ago
What is the total force acting on the ball in the diagram? How would you describe its velocity?
KonstantinChe [14]

Answer:

Velocity formulae should be used in order to know the answer

8 0
3 years ago
Read 2 more answers
A horizontal line on a velocity/time graph shows ____ acceleration.
Novay_Z [31]

Answer:

Zero (0)

Explanation:

A horizontal line will be no movement of negative of positive acceleration

6 0
3 years ago
Read 2 more answers
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