The net force on the car for either case will be zero, since the car is moving at a constant velocity.
<h3>Net force on the car</h3>
The net force on the car is the sum of all the forces acting on the car.
∑F = ma
<h3>When the car is on a level road</h3>
When the car is on a level road, the only two forces acting on the car is the applied force and frictional force of the road.
F - Ff = 0
The net force will be zero, since the car is moving at a constant velocity.
<h3>When the car is on uphill</h3>
The forces acting on the car at the uphill is the applied force, weight of the car acting downwards and the frictional force acting opposite direction.
F - Wsinθ - μFₙcosθ = 0
The net force will be zero, since the car is moving at a constant velocity.
Learn more about net force at constant velocity here: brainly.com/question/14392124
Answer:
3 and 2
May be
ok may be subscribeIsenberg Isenberg Ignatius
When the two air masses meet i think
Porque la matematica es imposible
Answer:
T=502.5N
Ax=171.8N
Explanation:
The computation of the tension T in the rope and the forces exerted by the pin at A is shown below:
vertical forces sum = Ay + Tsin20 + T - 245 - 883 = 0
Now
horizontal forces sum = Ax - Tcos70
Now Moment about B
-Ay × 4.8 + 245 × 2.4 + 883 × 1.8=0
Ay=453.6N
Now substitute in sum of vertical forces T=502.5N
Ax=171.8N
