Answer:
Explanation:
Given that,
Radius of the circular loop, r = 10 cm = 0.1 m
Current flowing in the loop, I = 3.6 A
Uniform magnetic field, B = 12 T
To find,
The magnetic dipole moment of the loop.
Solution,
Let M is the magnitude of magnetic dipole moment of the loop. We know that the product of current flowing and the area of cross section. Its formula is given by :
A is the area of circular wire
Therefore, the magnetic dipole moment of the loop is 
. Hence, this is the required solution.
Answer:
See below
Explanation:
East components are 10 and 12 cos 30 = 20.392 m/s
North component = 12 sin 30 = 6 m/s
Resultant velocity = sqrt ( 20.392^2 + 6^2) = <u>21.26 m/s </u>
direction arc tan (6/20.392) = <u>16.4 degrees N of east </u>
Analyze your attachment style and describe how this is being manifested in your significant relationships....
Answer:
- The size of a force
- The perpendicular distance from the pivot the line of action of force
Explanation:
Factors that affect the moment of a force are;
- The size of a force
- The perpendicular distance from the pivot the line of action of force
The magnitude of force applied is directly proportional to the moment of force in that for a perpendicular distance d, increased in force applied will result to a higher moment of force. When the perpendicular distance from the pivot is decreased while the force applied remains constant, the moment of force decreases.
i believe thaT IT IS B BUT PLEASE TELL ME IF IM WRONG I WAS JUST USING LOGIC
