Answer:
8.33 atm
Explanation:
Xe is 5 out of (4+5) or 5 / 9 ths of the gas present
5/9 * 15 atm = 8.33 atm
Answer:
17.92L or 17.92dm³1
Explanation:
number of moles of a gas = volume of that gas/ 22.4(S.V.P)
0.8 mol = x / 22.4
cross multiplication
x = 22.4 × 0.8
x = 17.92
:. the volume of 0.8 mol of nitrogen gas is 17.92dm³ or 17.92L
The mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.
<h3>What is the equation of the synthesis of water from hydrogen and oxygen?</h3>
The equation of the synthesis of water from hydrogen and oxygen is given as follows:
The grams of oxygen required is given below:
The equation of the combustion of propane is given as follows:
The mass of carbon dioxide produced is given below:
The equation of the reaction of copper and silver nitrate is given as follows:
Therefore, the mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.
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Answer:
I dont see a diagram,, can yu please attach an image so that we can answer it