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Marrrta [24]
3 years ago
15

How many moles of methane were in the erlenmeyer flask?

Chemistry
2 answers:
DanielleElmas [232]3 years ago
5 0

Since the question is incomplete, I can help you with a detailed explanation on how to calculate the number of moles of mehate in an erlenmeyer flask.


There are two possible scenaries for this question.


1) Scenary I. Known mass.


Whether you are given the mass or other information that permits to calculate the mass of methane, you can work with the molecular formula to calculate the number of moles, in this way:


i) Methane chemical formula: CH₄


ii) Molar masss: sum the mass of each element in the formula, using the atomic mass and number of atoms of each.


Molar mass = 12.011 g/mol + 4× 1.008 g/ mol = 16.043 g/mol


iii) Number of moles


Formula: number of moles = mass in grams / molar mass = mass in grams / 16.043 g/mol.


That is it. Use the last formula to calculate the number of moles of methane.


2) Scenary 2. P, T,and V known.


You do not know the mass but the conditions: temperature (T), volume (V), and pressure (P).


In this case you use the ideal gas equation:


PV = nRT, from which you clear for the number of moles (n):


n = PV/(RT).


Plug in the data of P, V and T in coherent unit system.


R is the universal law of gases, which you must also use with the appropiate units, depending on the units of P, V, and T used.


For example, R = 0.0821 atm×liter / (K×mol); and R = 8.314 KPa×liter/(mol×K).

Savatey [412]3 years ago
4 0
Methane Volume : O.O
Methane Mass: 0.100g
Molar Mass of Methane : 16.04 g/mol
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Explain the difference between the strength of an acid and the concentration of an acid​
Alinara [238K]

Answer:

Hydrogen Fluoride will dissolve glass & eat concrete; BUT mixed with water, it is very nasty - but fairly weak!

A strong acid EASILY donates a Proton (H+).

Look up dissociation of acids and the ones that give up that H+ is the strong one.

Explanation:

6 0
3 years ago
Estimate the solubility of m(oh)2 in a solution buffered at ph = 7.0, 10.0, and 14.0.
kherson [118]
<span>When M(OH)2 dissolves we have M(OH)2 which produces M2+ and 2OHâ’ pH + pOH=14 At ph =7; we have 7+pOH=14 pOH=14â’7 = 7 Then [OHâ’]=10^(â’pOH) [OH-] = 10^(-7) = 1* 10^(-7) At ph = 10. We have, pOH = 4. And [OH-] = 10^(-4) = 1 * 10^(-4) Finally ph = 14. We have, pOH = 0 And then [OH-] = 10^(-0) -----anything raised to zero power is 1, but (-0)... So [OH-] = 1</span>
4 0
3 years ago
How many liters of chlorine gas can react with 56.0 grams of calcium metal at standard temperature and pressure? Show all of the
Doss [256]
The balanced chemical reaction is:

<span>Ca + Cl2 =  CaCl2
</span>
We are given the amount of calcium metal to be used for this reaction. This will be the starting point for the calculations.

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5 0
3 years ago
Read 2 more answers
A student ran the following reaction in the laboratory at 671 K: 2NH3(g) N2(g) + 3H2(g) When she introduced 7.33×10-2 moles of N
vaieri [72.5K]

Answer:

Kc = 8.05x10⁻³

Explanation:

This is the equilibrium:

                 2NH₃(g)   ⇄     N₂(g)     +     3H₂(g)

Initially       0.0733

React         0.0733α          α/2                3/2α

Eq     0.0733 - 0.0733α    α/2                0.103

We introduced 0.0733 moles of ammonia, initially. So in the reaction "α" amount react, as the ratio is 2:1, and 2:3, we can know the moles that formed products.

Now we were told that in equilibrum we have a [H₂] of 0.103, so this data can help us to calculate α.

3/2α = 0.103

α = 0.103 . 2/3 ⇒ 0.0686

So, concentration in equilibrium are

NH₃ = 0.0733 - 0.0733 . 0.0686 = 0.0682

N₂ = 0.0686/2 = 0.0343

So this moles, are in a volume of 1L, so they are molar concentrations.

Let's make Kc expression:

Kc= [N₂] . [H₂]³ / [NH₃]²

Kc = 0.0343 . 0.103³ / 0.0682² = 8.05x10⁻³

3 0
3 years ago
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andrezito [222]

Based on the charge on the aluminium ion, 0.9 g of aluminium are deposited by 0.1 F of electricity.

<h3>What is electrolysis?</h3>

Electrolysis is the decomposition of a substance known as an electrolyte when electric current is passed through it.

The mass and hence moles an electrolyte deposited when current is passed through it depends on the charge on the ion.

Aluminium ion has a charge of +3 and requires 3F of electricity to deposit 1 mole or 27 g of aluminium

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mass of aluminium deposited = 0.9 g of aluminium.

Therefore, 0.9 g of aluminium are deposited by 0.1 F of electricity.

Learn more about electrolysis at: brainly.com/question/26050361

5 0
2 years ago
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