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PilotLPTM [1.2K]
3 years ago
9

Becomes caramel. He pushes

Chemistry
1 answer:
kozerog [31]3 years ago
5 0

Answer:

Turning Sugar into Caramel

Explanation:

You turn sugar into caramel by burning sugar. Burning sugar is a chemical change.

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What is the energy of a photon of yellow light with a frequency of 5.2 x 10¹⁴ Hz?<br><br>​
3241004551 [841]

Answer:

3.4x10⁻¹⁹J is the energy of the photon

Explanation:

To find the energy of a photon from its frequency we must use the equation:

E = hf

<em>Where E is the energy of the photon in J, our incognite</em>

<em>h is Planck's constant = 6.6262x10⁻³⁴Js</em>

<em>And f is the frequency = 5.2x10¹⁴Hz = 5.2x10¹⁴s⁻¹</em>

<em />

Replacing:

E = 6.6262x10⁻³⁴Js*5.2x10¹⁴s⁻¹

E = 3.4x10⁻¹⁹J is the energy of the photon

<em />

4 0
2 years ago
An 80.0 g sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and
harina [27]

Answer:

C=0.596\frac{J}{g\°C}

Explanation:

Hello there!

In this case, according to the first law of thermodynamics it is possible to compute the gained heat by the water as shown below:

Q=\Delta U+W\\\\Q=9185J+346J=9531 J

Thus, it is possible to solve for the specific heat of the gas as shown below:

Q=mC\Delta T\\\\C=\frac{Q}{m\Delta T}=\frac{9531J}{80.0g*(225-25)\°C}\\\\C=0.596\frac{J}{g\°C}

Best regards!

3 0
2 years ago
What is the energy of a photon of green light whose frequency is 6.85 X 1014/seC?
Anvisha [2.4K]

Frequency of photon = is 6.85 X 10¹⁴ sec⁻¹

Energy of photon , E = hv

where h is Planck's constant, v is the frequency of photon

E = 6.63 × 10⁻³⁴ J.s x 6.85 X 10¹⁴ s⁻¹

E = 4.54 x 10⁻¹⁹ J

Therefore, the energy of a photon of green light is 4.54 x 10⁻¹⁹ J.

8 0
2 years ago
The mineral stibnite, antimony(III) sulfide, is treated with hydrochloric acid to give antimony(III) chloride and hydrogen sulfi
jeka94
The balanced chemical reaction is written as:

Sb2S3 + 6HCl = 6SbCl<span>3 + 3H2S

We are given the amount of </span><span>antimony(III) sulfide to be used in the reaction. This is amount will be used for the calculations. We do as follows:

2.85 g Sb2S3  ( 1 mol / </span><span>339.715 g ) ( 6 mol SbCl3 / 1 mol Sb2S3 ) (</span> 228.13 g / mol ) = 11.48 g SbCl3
5 0
3 years ago
Scientific theories are usually
jasenka [17]

Answer:

B

Explanation:

Cuz they are supported once discovered and then widely spread then accepted

4 0
3 years ago
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