The wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.
Answer:
Explanation:
Since, wavelength, frequency and speed of sound waves are related to each other, we can determine a single parameter with the help of other two parameters. So in this case, the frequency of different notes are given along with their common speed. So as the frequency is inversely proportional to the wavelength then in this case, the wavelength of the notes will be maximum for C1 and minimum for 3951.1 Hz.
Wavelength = Speed / Frequency
Wavelength for C1 note = 340 / 32.7 =10.40 m
Similarly, the wavelength for A6 note = 340/1760=0.193 m
And, the wavelength for B7 note = 340/3951.1 = 0.086 m
So, the wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.
The name of this landmas is known as <em>
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Pangaea, was a supercontinent that existed during the late
Paleozoic and
early
Mesozoic eras. It formed approximately 300 million years ago and began to break apart after about 100 million years.
Theres an image of how this supercontinet looked
This question is incomplete.Here is complete one
Consider a telescope with a small circular aperture of diameter 2.0 centimeters.
If two point sources of light are being imaged by this telescope, what is the maximum wavelength (lambda) at which the two can be resolved if their angular separation is 3.0x10^-5 radians? Express your answer in nanometers
Answer:
λ =492nm
Explanation:
Given Data
diameter=2.0 cm
angular separation=3.0x10^-5 radians
λ=?
Solution
sin(theta) = 1.22 x λ /D
λ=(0.02×sin(3.0×10⁻⁵))/1.22
λ=492nm
Answer:
Explanation: work equals force times distance so 400x4=1600 joules
Answer:
Current
Explanation:
The equation you mentioned is also known as Ohm's law, which can be applied for any circuit containing a battery and one (or more) resistors:
where
V is the voltage
I is the current
R is the resistance
We can re-arrange the equation and rewrite it explicitely for I, the current, to match the equation mentioned in the text of the question, and we have:
