Answer:The FitnessGram PACER Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The test is used to measure a student's aerobic capacity as part of the FitnessGram assessment. Students run back and forth as many times as they can, each lap signaled by a beep sound.
Explanation:
Answer:
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
In such a way, since all the lead (II) is converted due to the excess of potassium chloride, the moles of lead (II) in the sample are computed from the mass of lead (II) sulfate:
Thus, since volume of the solution is 1.65 due to the fact that the addition of the reactants is not enough to significantly modify the reaction's volume, the resulting molar concentration of the lead (II) ions is:
Regards.
Answer:
molar composition of oxygen =0.2 (20%)
molar composition of hydrogen = 0.8 (20%)
Explanation:
Since hydrogen and oxygen react according to
2*H₂+ O₂ → 2*H₂O
according to the ideal gas law:
P₁*V=n₁*R*T (initial state)
P₂*V=n₂*R*T (final state)
dividing both equations
P₁/P₂ = n₁/n₂
then since 2 moles of hydrogen react for every mole of oxygen that reacts, thus oxygen that reacted "no" is
no = (n₁-n₂) 1/(1+2) = n₁ (1-n₂/n₁)/3
then
molar composition of oxygen = xo= no/n₁ = (1-n₂/n₁)/3 = (1-P₂/P₁)/3 = (1-0.4 atm/1 atm )/3 = 0.2 (20%)
then
molar composition of hydrogen = xh= 1- xo = 0.8 (20%)
to verify it , the number of initial moles n₁=remaining hydrogen + hydrogen that reacted + oxygen that reacted
and since 2 moles of hydrogen react for every mole of oxygen that reacts n₁= n₂ + (n₁-n₂) (2/3) + (n₁-n₂) (1/3) = n₂ + (n₁-n₂) = n₁
Answer:
29.9g acetone
37.8mL acetone
Explanation:
The reaction is:
acetone + 2 2.2-dimethylpropanal → 2,2,8,8-tetramethylnona-3,6-dien-5-one
<em>Acetone (0.791g/mL, 58.08g/mol); 2,2,8,8-tetramethylnona-3,6-dien-5-one (194.13g/mol)</em>
<em />
100g of product are:
100g×(1mol/194.13g) = <em>0.515mol 2,2,8,8-tetramethylnona-3,6-dien-5-one</em>
<em />
As 1 mole of product comes from 1 mole of acetone, moles of acetone are 0.515mol. In grams:
0.515mol acetone × (58.08g/mol) = <em>29.9g acetone</em>
Now, in mL are:
29.9g acetone × (1mL / 0.791g) = <em>37.8mL acetone</em>
