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Art [367]
3 years ago
12

What is the volume occupied by 3.70 moles of n2 gas at stp?

Chemistry
1 answer:
melisa1 [442]3 years ago
7 0
The conversion factor for volume at STP is \frac {1mol}{22.4L} or \frac{22.4L}{1mol}. Since we want volume, we would use \frac{22.4L}{1mol}. We conclude with the following calculations:

3.70molN_{2} * \frac {22.4LN_{2}}{1mol N_{2}} = 82.88LN_{2}

The answer is 82.88L N2
You might be interested in
40.32 kg NaHCO3
Alex17521 [72]

In 40.32 kg of NaHCO₃, there are 2.890 × 10²⁶ formula units of NaHCO₃.

<h3>What is a formula unit?</h3>

A formula unit is the empirical formula of any ionic or covalent network solid compound used as an independent entity for stoichiometric calculations.

  • Step 1: Convert 40.32 kg to g.

We will use the conversion factor 1 kg = 1000 g.

40.32 kg × (1000 g/1 kg) = 4.032 × 10⁴ g

  • Step 2: Convert 4.032 × 10⁴ g to moles.

We will use the molar mass of NaHCO₃ as the conversion factor.

4.032 × 10⁴ g × (1 mol/84.01 g) = 479.9 mol

  • Step 3: Convert 479.9 moles to formula units (fu).

We will use Avogadro's number as the conversion factor.

479.9 mol × (6.022 × 10²³ fu/1 mol) = 2.890 × 10²⁶ fu

In 40.32 kg of NaHCO₃, there are 2.890 × 10²⁶ formula units of NaHCO₃.

Learn more about formula units here: brainly.com/question/2165878

7 0
2 years ago
When 8.0 g H₂ react with 8.0 g O₂ in the reaction 2H₂ + O₂ → 2H₂O, what are the theoretical yield and the limiting reactant?
True [87]

Answer:

Now, we have to determine the limiting reagent.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g of

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂O

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.For, amount of oxygen left of unreacted, Only 24 g of oxygen will react.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.For, amount of oxygen left of unreacted, Only 24 g of oxygen will react.But 29 g is the given amount. Amount of oxygen unreacted = 29 - 24 = 5 g

7 0
3 years ago
Hydrogen gas and aqueous zinc chloride are produced by the reaction of aqueous hydrochloric acid and solid zinc . Write a balanc
Ymorist [56]

<em>1. Write out all the ions/elements and indicate whether they are reactants or products. </em>

<u>Reactants:</u>

Aqueous Hydrochloric Acid: HCl (H has a charge of +1 and Cl has a charge of 1-, so when an ionic bond forms they will form HCl).

Solid Zinc: Zn (since it is a solid zinc with no other forms of elements, the zinc is pure).

<u>Products:</u>

Hydrogen gas: H2 (it has to be H2 because Hydrogen is a diatomic element, and when by itself during reactions, will be H2 instead of H).

Aqueous Zinc Chloride: ZnCl2 (Zn has a charge of 2+ and Cl has a charge of 1-, so through an ionic bond, they will form ZnCl2).

<em>2. Using this information, you can then write out the unbalanced equation.</em>

HCl + Zn -> H2 + ZnCl2

<em>3. Next, indicate their states of matter and any aqueous solutions. </em>

HCl (aq) + Zn (s) -> H2 (g) + ZnCl2 (aq)

<em>4. Try different numbers until you get the same numbers of H, Cl, and Zn on both sides. </em>

2 HCl (aq) + Zn (s) -> H2 (g) + ZnCl2 (aq)

As you can see, the equation contains 2 Hydrogen atoms on both sides, 2 Chloride atoms on both sides, and 1 Zinc atom on both sides. The equation is chemically balanced.

5 0
4 years ago
If a radioisotope has a half life of 10 years, how much of the original material would remain after 40 years?
Anton [14]
1/8 would remain...
(1/2 is 10 years
1/4 is 20 years
1/8 is 40 years)

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
Describe how molecular motion and distance between molecules change as ice is heated to become a liquid and then a gas
MAXImum [283]

Answer:

Described in the explanation section

Explanation:

Ice is the solid phase of water and this phase, the water molecules usually have very little energy and therefore can't detach from each other. This is because the water molecules are closely packed together in a regular arrangement normally called lattice.

Now, when the ice is heated to become a liquid, the energy of the water molecules increases and thus some of them will have enough energy to overcome the intermolecular forces that had been keeping them closely packed in the ice phase. This will then make the water molecules to move further apart thereby forming liquid water.

Now, when the molecules are heated further, the liquid water will now turn into water vapor, which is the gas phase of water. The molecules in this gas phase will have more energy than in the liquid phase because the average distances between each of them will be much larger than the size of the molecules themselves.

8 0
3 years ago
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