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ycow [4]
3 years ago
5

For an isolated system, the law of conservation of momentum is valid: A. for inelastic collisions. B. for elastic collisions. C.

only when there are no collisions. D. for all types of collisions.
Physics
1 answer:
emmainna [20.7K]3 years ago
6 0
The correct answer is:
<span>D. for all types of collisions.

In fact, for an isolated system, the law of conservation of momentum is always valid. Instead, kinetic energy is conserved only when the collision is elastic, while for inelastic collisions kinetic energy is not conserved.</span>
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Avg sped = total distance/ total time = 1350 mi/ 5 hrs= 270mph (i dont know if ur teacher wants you to convert this to m/s) 

300miles are traveled in 1 hr. So, 300 *2hrs = 600 miles south
750/250= 3hrs north
Total distance = 600 miles + 750 miles= 1350 miles
Total time is =  3hrs + 2hrs= 5hrs
 



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4 years ago
A proton in a cyclotron is moving with a speed of 2.97×107 m/s in a circle of radius 0.568 m. 1.67 × 10−27 kg is the mass of the
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Answer:

B = 0.546 T,  F = 2.59 10⁻¹² N

Explanation:

The magnetic force is

            F = q v x B

We can calculate the magnitude of the force and find the direction by the right hand rule

          F = q v B sin θ

Let's use Newton's second law

         F = m a

Acceleration is centripetal

         a = v² / r

We substitute

       q v B sin θ = m v² / r

The angle between the field and the radius of the circle is 90º so sin 90 = 1

        q B = m v / r

        B = m v / q r

Let's calculate ’

       B = 1.67 10⁻²⁷ 2.97 10⁷ / (1.60 10⁻¹⁹ 0.568)

        B = 0.546 T

The foce is

         F = q v B

         F = 1.60 10⁻¹⁹ 2.97 10⁷ 0.546

         F = 2.59 10⁻¹² N

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3 years ago
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