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gogolik [260]
2 years ago
9

Charge is distributed uniformly on the surface of a large flat plate. the electric field 2 cm from the plate is 30 n/c. the elec

tric field 4 cm from the plate is:
Physics
1 answer:
AysviL [449]2 years ago
7 0
The electric field produced by a large flat plate with uniform charge density on its surface can be found by using Gauss law, and it is equal to
E= \frac{\sigma}{2\epsilon_0}
where
\sigma is the charge density
\epsilon_0 is the vacuum permittivity

We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
E=30 N/C
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How fast does water flow from a hole at the bottom of a very wide, 3.2 m deep storage tank filled with water
Nezavi [6.7K]

Answer:

the velocity of the water flow is 7.92 m/s

Explanation:

The computation of the velocity of the water flow is as follows

Here we use the Bernouli equation

As we know that

V_1 = \sqrt{2g(h_2 - h_1)}\\\\=\sqrt{2g(\Delta h)}  \\\\= \sqrt{2\times9.8\times3.2} \\\\= \sqrt{62.72}

= 7.92 m/s

Hence, the velocity of the water flow is 7.92 m/s

We simply applied the above formula so that the correct value could come

And, the same is to be considered

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A bowling ball weighing 71.2 N (16.0 lb) is attached to the ceiling by a 3.80-m rope. The ball is pulled to one side and release
Elina [12.6K]

Answer:

a) For this case we want to find the acceleration of the bowling ball, and we now that the only acceleration for this case would be the centrifugal acceleration becuase since the pendulum is in phase with the equilibrium point the tangential acceleration is 0, and if we find the centrifugal acceleration we got:

a= \frac{v^2}{R}= \frac{(4.2 m/s)^2}{3.8 m}=4.64 m/s^2

b) For this case the tendsion is an opposite force against the weight and the centrifugal force acting in the ball so then we can find the tension like this:

T= mg +ma

In order to find the mass we know that W=mg and solving for m we got:

m =\frac{W}{g}=\frac{71.2 N}{9.8 m/s^2}=7.265 kg

And replacing into the tension we got:

T= m(g+a) =7.265 kg *(9.8 m/s^2 +4.64 m/s^2)=104.907 N

Explanation:

For this case we have the following data given:

W= 71.2 N represent the weigth for the object

R=3.8 m the length of the rope or the radius

v= 4.2 m/s represent the velocity of the bowling ball

Part a

For this case we want to find the acceleration of the bowling ball, and we now that the only acceleration for this case would be the centrifugal acceleration becuase since the pendulum is in phase with the equilibrium point the tangential acceleration is 0, and if we find the centrifugal acceleration we got:

a= \frac{v^2}{R}= \frac{(4.2 m/s)^2}{3.8 m}=4.64 m/s^2

Part b

For this case the tendsion is an opposite force against the weight and the centrifugal force acting in the ball so then we can find the tension like this:

T= mg +ma

In order to find the mass we know that W=mg and solving for m we got:

m =\frac{W}{g}=\frac{71.2 N}{9.8 m/s^2}=7.265 kg

And replacing into the tension we got:

T= m(g+a) =7.265 kg *(9.8 m/s^2 +4.64 m/s^2)=104.907 N

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