The thermosphere is the layer of the Earth's atmosphere directly above the mesosphere and below the exosphere. Within this layer of the atmosphere, ultraviolet radiation causes photoionization/photodissociation of molecules, creating ions in the ionosphere.
In trajectory, acceleration vector is not the same with the velocity vector but it depends on the change in velocity. The acceleration path is perpendicular to the velocity vector path. The Correct answers are:
a.) D
b.) B
c.) C
d.) A
A Vector is a quantity that has both magnitude and direction.
Given that a ball is fired from a cannon at point 1 and follows the trajectory shown in the figure.
a.) The vector best represents the ball's velocity at position 2 is D
b.) The vector best represents the ball's acceleration at point 2 is B
c.) Which vector best represents the ball's velocity at position 3 = C
d.) Which vector best represents the ball's acceleration at point = A
In trajectory, acceleration vector is not the same with the velocity vector but depends on the change in velocity. The acceleration path is perpendicular to the velocity vector path.
At point 3, since the ball path is parabolic, the velocity at that point is not equal to zero but will tend to take a horizontal path.
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a,c,d, is your answer I think I hope it helps
Answer:
Check Explanation
Explanation:
Ampere's Law gives the expression for the magnetic field produced by current in a current carrying material.
Mathematically, it is explained that the product of permeability and current is equal to the sum of the dot product of the magnetic field in the direction of the length elements and the length elements.
μ₀I = ∫ B.dl (note that this integral is around the entire loop of current carrying material)
This law is valid for infinite current carrying wires because the magnetic field around such infinite current carrying wire is symmetrical.
The magnetic field around a finite length of wire is non-symmetrical and the current isn't continuous.
For Ampere's Law to work, the magnetic field around the wire must be symmetric, for straightforward computation and the current in the wire needs to be continuous, not cut short at the edges which makes the field around the wire non-symmetrical.
So, this condition is interlinked.
Hence, it is evident that only option A is absolutely correct.
Options C and D on their own aren't totally correct, but in conjunction with option E, they are correct.
Hope this Helps!!!
is the charge density
is the vacuum permittivity