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adelina 88 [10]
4 years ago
5

What are anticlines and synclines?

Physics
1 answer:
vesna_86 [32]4 years ago
3 0
<span>d. They are types of folds created by compressional stresses.</span>. 
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50. The potential energy of a spring is 0.3 J when it is compressed 0.04 m to the left of its equilibrium
lozanna [386]

Answer:

Your answer should be A. 0.25 J and moving to the right

Explanation:

6 0
3 years ago
Given a die, would it be more likely to get a single 6 in six rolls, at least two 6s in twelve rolls, or at least one-hundred 6s
vichka [17]

Answer:

Explanation:

In first case we are interested in one time 6 in six rolls

Thus probability = number of chances required/Total chances

= 1/6

Similarly in the second case probability = 2/12 = 1/6

In the same way in last case probability = 100/600 = 1/6

The probability is the same . Thus all the cases has equal chances  

4 0
3 years ago
A box weighing 43.2 N is pulled horizontally until it slides uniformly lat a constant
GREYUIT [131]

Your diagram should include four forces:

• the box's weight, pointing down (magnitude <em>w</em> = 43.2 N)

• the normal force, pointing up (mag. <em>n</em>)

• the applied force, pointing the direction in which the box is sliding (mag. <em>p</em> = 6.30 N, with <em>p</em> for "pull")

• the frictional force, pointing oppoiste the applied force (mag. <em>f</em> )

The box is moving at a constant speed, so it is inequilibrium and the net forces in both the vertical and horizontal directions sum to 0. By Newton's second law, we have

<em>n</em> + (-<em>w</em>) = 0

and

<em>p</em> + (-<em>f</em> ) = 0

So then the forces have magnitudes

<em>w</em> = 43.2 N

<em>n</em> = <em>w</em> = 43.2 N

<em>p</em> = 6.30 N

<em>f</em> = <em>p</em> = 6.30 N

5 0
3 years ago
How far does light travel in the time it takes sound to travel 1 cm in air at 20°c?
kykrilka [37]
The speed of sound at 20^{\circ}C is approximately v=343 m/s. The distance covered by the sound wave is
s=1 cm=0.01 m
And the time it takes is
t= \frac{S}{v}= \frac{0.01 m}{343 m/s}=2.9 \cdot 10^{-5} s

Now we want to find how far the light travels during this time. Light travels at speed c=3 \cdot 10^8 m/s, therefore the distance it covers during this time is
S=ct = (3 \cdot 10^8 m/s)(2.9 \cdot 10^{-5} s)=8700 m
8 0
3 years ago
seagull is flying at a rate of 20 miles per hour south, it encounters wind blowing 20 miles per hour north. What is the resultan
KiRa [710]

Answer:

the winds will make the bird stop

Explanation:

is basically 20 - 20

8 0
3 years ago
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