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Akimi4 [234]
2 years ago
6

What is the concentration of each ion in a 0.525 mol/L solution of magnesium chloride? mg=? cl=?

Chemistry
1 answer:
Vladimir [108]2 years ago
3 0

Answer:

Mg⁺² = 0.525 mol/L

Cl⁻ = 1.05 mol/L

Explanation:

The formula for magnesium chloride is MgCl₂, and in a solution the following process takes place:

  • MgCl₂ → Mg⁺² + 2Cl⁻

By analyzing the stoichiometric coefficients, we can tell that <em>the concentration of Mg⁺² ions is the same as the concentration of MgCl₂</em>, while the <em>Cl⁻ concentration is twice that value</em>.

In other words:

  • Mg⁺² concentration = MgCl₂ concentration = 0.525 mol/L
  • Cl⁻concentration = 2 * MgCl₂ concentration = 1.05 mol/L
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For this question, we have analyzed the <u>substrate</u> and the <u>base/nucleophile</u>. The substrate, in this case, is 1-iodohexane and the base/nucleophile is potassium tert-butoxide.

<u>Substrate</u>

<u />

In the 1-iodohexane the iodide "I" is bonded to a primary carbon (carbon 1). Therefore we will have a <u>primary substrate</u>. If we have a primary substrate an Sn1 can not take place. We can not have a <u>primary carbocation</u> due to this instability. So, we can disccard options A) and B).

<u>Base/nucleophile</u>

<u />

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With both analyses, the answer is C).

See figure 1

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