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3 years ago

What is the name of the compound that goes with the chemical formula MgCl2

Physics

1 answer:

frez [133]3 years ago

8 0

Magnesium chloride is your answer

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Which of the following is equal to an impulse of 15 units?

strojnjashka [21]

Answer:

B) Force = 7.5, Time = 2 is equal to an impulse of 15 units

3 0

3 years ago

Read 2 more answers

If the mass of a

mixer [17]

Answer:

The final acceleration becomes (1/3) of the initial acceleration.

Explanation:

The second law of motion gives the relationship between the net force, mass and the acceleration of an object. It is given by :

$F=ma$

m = mass

a = acceleration

According to given condition, if the mass of a sliding block is tripled while a constant net force is applied. We need to find how much does the acceleration decrease.

$a=\dfrac{F}{m}$

Let a' is the final acceleration,

$a'=\dfrac{F}{m'}$

m' = 3m

$a'=\dfrac{F}{3m}$

$a'=\dfrac{1}{3}\times \dfrac{F}{m}$

$a'=\dfrac{1}{3}\times a$

So, the final acceleration becomes (1/3) of the initial acceleration. Hence, this is the required solution.

5 0

3 years ago

If a 2 x 10^-4C test charge is given 6.5J of energy, determine the electric potential difference.

Gwar [14]

Answer:

The electric potential difference is 32500 volt.

Explanation:

Given that,

Charge $q=2\times10^{-4}C$

Energy = 6.5 J

We need to calculate the electric potential difference

Potential difference :

Potential difference is equal to the energy divide by charge.

Using formula of potential difference

$V=\dfrac{E}{Q}$

$V=\dfrac{6.5}{2\times10^{-4}}$

$V=32500\ volt$

Hence, The electric potential difference is 32500 volt.

8 0

3 years ago

Dr. Man was studying a fossil from a dig in a desert when he noticed that the organism had evidence of fins.

Stells [14]

What organism? Picture?

6 0

2 years ago

What frequency is received by the ambulance after reflecting from a wall near the person watching the oncoming ambulance (as in

Zepler [3.9K]

Answer:

900.48925 Hz

979.9785 Hz

Explanation:

$v_a$ = Relative velocity of ambulance = $109\ km/h=\dfrac{109}{3.6}$

$v_w$ = Velocity of wall = 0

v = Velocity of sound in air = 343 m/s

From doppler effect we have

$f=f'\dfrac{v+v_w}{v-v_a}\\\Rightarrow f=821\dfrac{343+0}{343-\dfrac{109}{3.6}}\\\Rightarrow f=900.48925\ Hz$

The frequency of sound is 900.48925 Hz

When the wall acts like a source

$f=f'\dfrac{v+v_a}{v-v_w}\\\Rightarrow f=900.48925\dfrac{343+\dfrac{109}{3.6}}{343-0}\\\Rightarrow f=979.9785\ Hz$

The frequency of sound is 979.9785 Hz

4 0

3 years ago