The friction force does the greatest magnitude of work on the crate
Consider all four forces. The normal force does no work at all, since there is no motion in the direction of that force, perpendicular to the ramp. The force of gravity is smaller than the force of friction, since you still need to push the crate to get constant velocity. The force of you pushing is also smaller than the force of friction, since you are moving down a ramp, and are therefore assisted by gravity. Therefore the force doing greatest magnitude of work is the force of friction. Note that, even though the frictional work is negative, it still has the greatest magnitude
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Answer: Its in explanation.
Explanation:
Because the electroscope is made from conducting material, some of its electrons move up to the top of the electroscope to be near the charged rod when the rod is held close.
The spin quantum number is represented by the symbol m s a nd has the possible values +1/2.-1/ corresponding to the two directions of the electron's magnetic field.
The magnetic quantum quantity tells us what number of orbitals there are in a subshell and the feasible orientations of those orbitals. Its value is dependent on the angular momentum quantum range.
The magnetic discipline is an area in area close to a magnet or an electric contemporary wherein a physical area is produced from a shifting electric rate that creates force on some other shifting electric rate. An instance of a magnetic field is the Earth's magnetic
All magnets have north and south poles. contrary poles are drawn to every other, whilst the identical poles repel each different. when you rub a chunk of iron alongside a magnet, the north-in search of poles of the atoms in the iron line up inside the identical route. The force generated by using the aligned atoms creates a magnetic subject.
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There all diffrent speeds
Answer:
(C) greater than zero but less than 45° above the horizontal
Explanation:
The range of a projectile is given by R = v²sin2θ/g.
For maximum range, sin2θ = 1 ⇒ 2θ = sin⁻¹(1) = 90°
2θ = 90°
θ = 90°/2 = 45°
So the maximum horizontal distance R is in the range 0 < θ < 45°, if θ is the angle above the horizontal.
