Explanation:
It is given that,
Force applied to object, 
Position,
(b) The cross product of force and position vector is used to find the net torque about the z axis. It is given by :



or

The torque is acting in -z axis.
(a) The magnitude of torque is given by :


Hence, this is the required solution.
The equation for the de Broglie wavelength is:
<span>λ = (h/mv) √[1-(v²/c²)], </span>
<span>where h is Plank's Constant, m is the rest mass, v is velocity, and c is the velocity of light in vacuum. However, if c>>v (and it is, in this case) then the expression under the radical sign approaches 1, and the equation simplifies to: </span>
<span>λ = h/mv. </span>
<span>Substituting, (remember to convert the mass to kg, since 1 J = 1 kg·m²/s²): </span>
<span>λ = (6.63x10^-34 J·s) / (0.0459 kg) (72.0 m/s) = 2.00x10^-34 m.</span>
Answer:
wallah i don't understand anything with my stoopid brain
Explanation:
I believe it is speed.
Hope this helps!